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if m and n are integers, is m odd? (1) n+m is odd (2) n+m =

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if m and n are integers, is m odd? (1) n+m is odd (2) n+m = [#permalink]  14 Jul 2010, 13:44
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if m and n are integers, is m odd?

(1) n+m is odd
(2) n+m = n^2 + 5
[Reveal] Spoiler: OA
Manager
Joined: 16 Feb 2010
Posts: 236
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Kudos [?]: 22 [0], given: 16

Re: m odd? [#permalink]  14 Jul 2010, 13:46
zisis wrote:
if m and n are integers, is m odd?

(1) n+m is odd
(2) n+m = n^2 + 5

1 is insuf
2 is insuf for me

let me explain:
m = n^2 - n + 5
thus, if n =0, m=1-0+5= 6 thus even
if n=1, m=1-1+5 = 5 thus odd...

what am i missing?
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Re: m odd? [#permalink]  14 Jul 2010, 13:55
(1) n,m could be odd,even ore even,odd. insufficient

(2) m = n^2 - n + 5 or m = odd|even - odd|even + odd = (odd - odd)|(even - even) + odd = even + odd = odd. sufficient.

zisis wrote:
if m and n are integers, is m odd?

let me explain:
m = n^2 - n + 5
thus, if n =0, m=1-0+5= 6 thus even
if n=1, m=1-1+5 = 5 thus odd...

what am i missing?

0^2 = 0.
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Manager
Joined: 16 Feb 2010
Posts: 236
Followers: 2

Kudos [?]: 22 [0], given: 16

Re: m odd? [#permalink]  14 Jul 2010, 13:57
walker wrote:
(1) n,m could be odd,even ore even,odd. insufficient

(2) m = n^2 - n + 5 or m = odd|even - odd|even + odd = (odd - odd)|(even - even) + odd = even + odd = odd. sufficient.

zisis wrote:
if m and n are integers, is m odd?

let me explain:
m = n^2 - n + 5
thus, if n =0, m=1-0+5= 6 thus even
if n=1, m=1-1+5 = 5 thus odd...

what am i missing?

0^2 = 0.

aaaaaaaaaaaaaaaaaaaaaaaaaa
it s the other way round
2^0 = 1 and not 0^2 = 1
aaaaaaaaaa
going mental
thanks
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Re: m odd? [#permalink]  14 Jul 2010, 14:07
1
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zisis wrote:
if m and n are integers, is m odd?

(1) n+m is odd
(2) n+m = n^2 + 5

(1) n+m=odd, sum of two integers is odd only if one is odd and another is even, hence m may or may not be odd. Sufficient.

(2) n+m=n^2+5 --> m+5=n^2-n --> m+5=n(n-1), either n or n-1 is even hence n(n-1)=even --> m+5=m+odd=even --> m=odd. Sufficient.

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Re: m odd?   [#permalink] 14 Jul 2010, 14:07
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