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If m and n are integers, then what is the value of ( 1)^m +

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Intern
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If m and n are integers, then what is the value of ( 1)^m + [#permalink] New post 01 Mar 2011, 00:00
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A
B
C
D
E

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25% (03:05) correct 75% (01:03) wrong based on 6 sessions
If m and n are integers, then what is the value of (–1)^m + (–1)^n + (–1)^m · (–1)^n ?
(1) m = 23522101
(2) n = 63522251
Director
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Re: don't know how to crack [#permalink] New post 01 Mar 2011, 00:18
Hi,
If you try to group the terms then you will see the solution.
[(-1)^m]*[(-1)^n+(1)]+[(-1)^n]

From A we know that m is odd so the sign will be neg. So no matter what the sign of n is the ans is -1.
from b we know that n is odd which means that the sign is neg. The term in the [] is 0, and the ans is -1.

Hope it helps
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Re: don't know how to crack [#permalink] New post 01 Mar 2011, 01:03
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The given expression is (-1)^m+(-1)^n+(-1)^m.(-1)^n

From statement 1, m is odd so (-1)^m = -1

Substituting this value in equation gives us -1 +(-1)^n - (-1)^n = -1

So, sufficient

From statement 2, n is odd so (-1)^n = -1

Substituting this value in equation gives us -1 +(-1)^m - (-1)^m = -1

So, sufficient

Hence , answer D
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Re: don't know how to crack [#permalink] New post 01 Mar 2011, 08:43
Answer should be D.
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Joined: 14 Dec 2010
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Concentration: Technology, Entrepreneurship
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Re: don't know how to crack [#permalink] New post 01 Mar 2011, 23:29
I feel substituting is faster than grouping.D it is.
Re: don't know how to crack   [#permalink] 01 Mar 2011, 23:29
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If m and n are integers, then what is the value of ( 1)^m +

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