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Re: If m and n are positive integers is m/n an integer? [#permalink]
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If \(m\) and \(n\) are positive integers is \(\frac{m}{n}\) an integer?

(1) \(m\) is a multiple of 14. Not sufficient as no info about \(n\).

(2) \(n\) is a divisor of 14. Not sufficient as no info about \(m\).

(1)+(2) As from (2) \(n\) is a divisor of 14 then it must be a divisor of every multiple of 14, therefore it's a divisor of \(m\) too. Sufficient.

Answer: C.

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Re: If m and n are positive integers is m/n an integer? [#permalink]
Bunuel wrote:
If \(m\) and \(n\) are positive integers is \(\frac{m}{n}\) an integer?

(1) \(m\) is a multiple of 14. Not sufficient as no info about \(n\).

(2) \(n\) is a divisor of 14. Not sufficient as no info about \(m\).

(1)+(2) As from (2) \(n\) is a divisor of 14 then it must be a divisor of every multiple of 14, therefore it's a divisor of \(m\) too. Sufficient.

Answer: C.

M01-06


This question asks is m a multiple of "n"?

St 1

M is a multiple of 14- obviously insufficient no info about n - we just know

M/ 7 x 2 = some integer X therefore M= 7 x 2 x K (some integer)

St 2

N is a divisor of 14 just means N is a factor of 14- obiously insuff no info about M

St 1 and St 2

7 x 2 x k/ any factor of 14 = integer

7 x 2 x k / 14 = integer for example as Bunuel explained

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Re: If m and n are positive integers is m/n an integer? [#permalink]
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Re: If m and n are positive integers is m/n an integer? [#permalink]
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