Find all School-related info fast with the new School-Specific MBA Forum

It is currently 21 Aug 2014, 04:21

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If M and N are positive integers that have remainders of 1

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Intern
Intern
avatar
Joined: 14 Jul 2005
Posts: 44
Location: California
Followers: 1

Kudos [?]: 4 [0], given: 0

If M and N are positive integers that have remainders of 1 [#permalink] New post 16 Nov 2006, 21:10
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10

Can anyone show me an easy way of solving this...
SVP
SVP
User avatar
Joined: 08 Nov 2006
Posts: 1560
Location: Ann Arbor
Schools: Ross '10
Followers: 12

Kudos [?]: 161 [0], given: 1

GMAT Tests User
 [#permalink] New post 16 Nov 2006, 21:34
M=6n1+1
N=6n2+3

M+N = 6(n1+n2)+4=6(x)+4

So, M+N will be a multiple of 6, + 4.

Except 86, all the other values meet this criteria.

hence the answer is 86.
GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jul 2004
Posts: 5097
Location: Singapore
Followers: 17

Kudos [?]: 136 [0], given: 0

GMAT Tests User
 [#permalink] New post 16 Nov 2006, 22:04
M = 6n + 1
N = 6t + 3

M+n = 6(n+t) + 4 = 2(3(n+t) + 2)

A - (86/2) - 2 = 41 <-- not divisible by 3
B - (52/2) - 2 = 48 <-- divisible by 3
C - (34/2) - 2 = 15 <-- divisible by 3
D - (28/2) - 2 = 12 <-- divisible by 3
E - (10/2) - 2 = 3 <--- divisible by 3

Ans A
Manager
Manager
User avatar
Joined: 03 Jul 2005
Posts: 195
Location: City
Followers: 1

Kudos [?]: 2 [0], given: 0

GMAT Tests User
 [#permalink] New post 16 Nov 2006, 22:28
Another approach

(m + n) / 6 = x + 4

6x + 24 = 86, x = 7

All other numbers when tested are not divisibly by 6 hence A is the answer
Director
Director
User avatar
Joined: 05 Feb 2006
Posts: 904
Followers: 1

Kudos [?]: 33 [0], given: 0

GMAT Tests User
 [#permalink] New post 16 Nov 2006, 23:29
My way:
Pick numbers

m=7
n=9

m+n=16...divide by 6....remainder is 4

Now look at the answer choices. Divide each value by 6 and look where the raimainder isn't 4.

A
SVP
SVP
User avatar
Joined: 05 Jul 2006
Posts: 1542
Followers: 5

Kudos [?]: 67 [0], given: 39

 [#permalink] New post 17 Nov 2006, 03:13
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10

m= 6x+1

n= 6y+3

m+n= 6x+6y+4

86/6= 14 2/6 ( remainder is 2 not 4

my answer is A
  [#permalink] 17 Nov 2006, 03:13
    Similar topics Author Replies Last post
Similar
Topics:
3 if M and N are positive integers that have remainders of 1 el1981 9 04 Mar 2008, 19:07
If M and N are positive integers that have remainders of 1 yogachgolf 3 15 Nov 2007, 13:03
If M and N are positive integers that have remainders of 1 Ravshonbek 2 23 Aug 2007, 16:23
If M and N are positive integers that have remainders of 1 Amit05 3 18 May 2007, 21:50
If M and N are positive integers that have remainders of 1 lan583 2 26 Aug 2006, 16:28
Display posts from previous: Sort by

If M and N are positive integers that have remainders of 1

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.