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If M and N are positive integers that have remainders of 1 [#permalink]

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04 Jun 2007, 21:05

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If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

Damn iamba, what a complicated way to look at it. The problem is much easier than that.

If A/6 gives a remainder of 1 and B/6 gives a remainder of 3 then (A+B)/6 should give a remainder of 1+3 = 4

Now we just look at all the options. E is fine 10 % 6 = 4 (% just means remainder when u divide). In fact the only one that doesnt fit the bill is option A where 86%6 = 2

**** iamba, what a complicated way to look at it. The problem is much easier than that.

If A/6 gives a remainder of 1 and B/6 gives a remainder of 3 then (A+B)/6 should give a remainder of 1+3 = 4

Now we just look at all the options. E is fine 10 % 6 = 4 (% just means remainder when u divide). In fact the only one that doesnt fit the bill is option A where 86%6 = 2

It looks to me like your reasoning is the same as his, except he put it into algebraic form

I don't understand why not E
Can anybody draw an example when Mand N divided by 6 have remainders of 1 and 3, and M+N=10?
M and N must be positive though....

M+N CAN have a value of ten and satisfying the conditions mentioned in the question. THe problem asks for a value that can NOT be for M+N.

The problem says: If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6.
So M must be divided by 6, not by 3
If M=3 then 3/6 does not give remainder 3