Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If M and N are positive integers that have remainders of 1 [#permalink]

Show Tags

04 Jun 2007, 22:05

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

Damn iamba, what a complicated way to look at it. The problem is much easier than that.

If A/6 gives a remainder of 1 and B/6 gives a remainder of 3 then (A+B)/6 should give a remainder of 1+3 = 4

Now we just look at all the options. E is fine 10 % 6 = 4 (% just means remainder when u divide). In fact the only one that doesnt fit the bill is option A where 86%6 = 2

**** iamba, what a complicated way to look at it. The problem is much easier than that.

If A/6 gives a remainder of 1 and B/6 gives a remainder of 3 then (A+B)/6 should give a remainder of 1+3 = 4

Now we just look at all the options. E is fine 10 % 6 = 4 (% just means remainder when u divide). In fact the only one that doesnt fit the bill is option A where 86%6 = 2

It looks to me like your reasoning is the same as his, except he put it into algebraic form

I don't understand why not E
Can anybody draw an example when Mand N divided by 6 have remainders of 1 and 3, and M+N=10?
M and N must be positive though....

M+N CAN have a value of ten and satisfying the conditions mentioned in the question. THe problem asks for a value that can NOT be for M+N.

The problem says: If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6.
So M must be divided by 6, not by 3
If M=3 then 3/6 does not give remainder 3