Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 25 Sep 2016, 00:17

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If M and N are positive integers that have remainders of 1

Author Message
Manager
Joined: 11 May 2007
Posts: 106
Followers: 1

Kudos [?]: 34 [0], given: 0

If M and N are positive integers that have remainders of 1 [#permalink]

Show Tags

15 Nov 2007, 14:03
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
SVP
Joined: 29 Aug 2007
Posts: 2492
Followers: 67

Kudos [?]: 707 [0], given: 19

Show Tags

15 Nov 2007, 14:13
yogachgolf wrote:
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10

A. any integer that fits to the expression (6k+4) is not the answer. 86 = 6k+2, so it is the required answer..
SVP
Joined: 05 Jul 2006
Posts: 1515
Followers: 5

Kudos [?]: 256 [0], given: 39

Show Tags

16 Nov 2007, 02:04
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10

m= 6k+1 , N = 6x+3

m+n = 6k+6x+4 = 2(3k+3x+2)

devide given by 2 ( 43-26-17-14-5)

now subtract 2 from each and see which is not a multiple of 3

(41 - 24 - 15 - 12 - 3)

41 is out , ie: answer is A
Manager
Joined: 20 Sep 2006
Posts: 58
Followers: 1

Kudos [?]: 15 [0], given: 0

Show Tags

16 Nov 2007, 04:12
yogachgolf wrote:
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10

Ok my theory is that in this case when M+N is divided by 6 the remainder has to be 3+1=4

Only 86 does not satisfy this condition hence Ans is A).
Re: Positive Integers   [#permalink] 16 Nov 2007, 04:12
Display posts from previous: Sort by