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If M and N are positive integers that have remainders of 1

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If M and N are positive integers that have remainders of 1 [#permalink] New post 19 Nov 2009, 13:43
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If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
[Reveal] Spoiler: OA

Last edited by Bunuel on 24 Apr 2012, 04:25, edited 1 time in total.
Edited the question and added the OA
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Re: M+N [#permalink] New post 19 Nov 2009, 13:56
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sagarsabnis wrote:
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10

Guys i am going mad for this question according to me the answer should be E but OA is A please explain how come it cannot be 10


M=6p+1, where p is integer >=0, so M can be 1, 7, 13, etc.
N=6q+3. where q is integer >=0, so N can be 3, 9, 15, etc.

M+N=6(p+q)+4, hence M+N is multiple of 6 plus 4 = 10, 16, 22, 28, 34, etc.

Only answer which is not of this type is 86, 86=13*6+2

Answer: A.

Hope it's clear.
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Re: M+N [#permalink] New post 19 Nov 2009, 14:31
but still can you give me the the value of M and N which will add up to 10. If you check the other way round the least numbers are 7 and 9 which adds up to 16 so how come 10 is possible?
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Re: M+N [#permalink] New post 19 Nov 2009, 14:43
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sagarsabnis wrote:
but still can you give me the the value of M and N which will add up to 10. If you check the other way round the least numbers are 7 and 9 which adds up to 16 so how come 10 is possible?


The problem in your reasoning is that you are not considering the values of M and N when, p and q are 0. If you do you'll get the least values: M=1 and N=3. So if you take the value of M when p=1 and value of N when q=0 you'll get:

M=7 and N=3 --> M+N=10.
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Re: M+N [#permalink] New post 19 Nov 2009, 14:47
Yeah now i do get it...Thanks mate!!!
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Remainders [#permalink] New post 01 May 2010, 12:27
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

a) 86
b) 52
c) 34
d) 28
e) 10

[Reveal] Spoiler:
Correct Answer: A


This question is fairly easy, but I don't get it, why 10 is not false.
When divided by 6, the smallest numbers that have a remainder of 1 and 3, respectively, are 7 and 9. 7+9=16.
So I don't get it, why 10 is correct.

Can someone please explain. I hope I don't have a error in thinking about this. ;-)
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Re: M+N [#permalink] New post 31 Aug 2010, 23:28
The smallest numbers are 1 and 3:
1 div by 6 = 0 with remainder if 1
3 divided 6 =0 with remainder of 3

so 10 could be 7+3 => 7 gives a remainder of 1 and 3 gives a remainder of 3 when divided by 6
or 1+9 => 9 gives a remainder of 3 and 1 gives a remainder of 1 when divided by 6
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If M and N are positive integers [#permalink] New post 24 Apr 2012, 01:53
19. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
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Re: If M and N are positive integers [#permalink] New post 24 Apr 2012, 02:53
My Approach:

When m and n are divided by 6, their remainders are 1 and 3.

In order to have a remainder of 1, M must be 7,13,19, 25 and so on. We can set up an equation: 6*n + 1 for every number M has to be. The same is with N. Their we have 9,15,21,27 etc. = 6*n+9.

If we sum it up, we have: 16+12n.

Now we can test every solution and the one that doesen't work is solution A.

16 + 12n = 86

12n = 74

n = 6,1666 <- no integer.

:)

Sorry for my english.:/
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Re: If M and N are positive integers [#permalink] New post 24 Apr 2012, 04:27
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shikhar wrote:
19. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10


Merging similar topics. Please ask if anything remains unclear.
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RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

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Re: If M and N are positive integers that have remainders of 1 [#permalink] New post 24 Apr 2012, 04:54
I did it this way
M=6p+1
N=6q+1

We need M+N=6p+1+6q+3=6(p+q)+4

Pick numbers for p & q
Since it is an addition of p & q and the answer to this expression should be an integer (because all the numbers being added are integers),
we just need to choose values so that we get integer multiples of 6 so
p+q=0 ; M+n = 4
p+q=1 ; M+N = 10
P+q=2 ; M+N = 16

and so on, so basically you get something like - 4,10,16,22,28,34,..... all the other options were turning up.

Then I directly tried p+q=12 because it was closer to 86 for the first option, i got 76, then tried with 13 - got 84, 14 got 90.. no 86.

So Answer A.

Is the approach correct? :)
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Re: If M and N are positive integers that have remainders of 1 [#permalink] New post 24 Apr 2012, 09:33
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nsvarunns wrote:
I did it this way
M=6p+1
N=6q+1

We need M+N=6p+1+6q+3=6(p+q)+4


Your approach was not wrong but a little cumbersome. Instead of picking values for p and q and trying to get to the options, pick the options and find out whether they suit this format.

52 = 6*8 + 4 so p+q = 8. Hence 52 can be the value of M+N
Similarly check for other options. At every step, you get closer to the solution else you could end up waiting for a long time before you get 4 of the 5 options.
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Re: If M and N are positive integers that have remainders of 1 [#permalink] New post 24 Apr 2012, 18:08
thanks Karishma. Will keep that in mind. It did take a long time for me to get it through.
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Re: If M and N are positive integers that have remainders of 1 [#permalink] New post 25 Apr 2012, 10:18
1+3=4
Using six times table to recognize the the nearest integer uner each option i.e.- 6*4 =24.
Whichever answer does not have four as a remainder wins the selection.

A

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Re: If M and N are positive integers that have remainders of 1 [#permalink] New post 25 Apr 2012, 19:34
use the options given to find which one satisfies the solution
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Re: If M and N are positive integers that have remainders of 1 [#permalink] New post 19 Oct 2012, 00:22
sagarsabnis wrote:
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10


M & N are divided by 6 : R =1 & 3 resp

M+ N divided by 6 : R 1+ 3 = 4

So divide the options by 6 .. & R should be 4.

Only ..86 has a remiander of 2 .....instead of 4..

Answer A
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Re: If M and N are positive integers [#permalink] New post 10 Jan 2013, 00:55
Bunuel wrote:
shikhar wrote:
19. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10


@bunuel..why are we considering the integers 1 and 3 in the list of integers when the stem question says that when each of the numbers is divided by six,the remainder is 1 and 3 respectively..when 1 is divided by six am sure we would not get 1 as a remainder neither would we get 3 as a remainder when the integer 3 is divided by 6

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Re: If M and N are positive integers [#permalink] New post 10 Jan 2013, 03:42
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chiccufrazer1 wrote:
Bunuel wrote:
shikhar wrote:
19. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?

(A) 86
(B) 52
(C) 34
(D) 28
(E) 10


@bunuel..why are we considering the integers 1 and 3 in the list of integers when the stem question says that when each of the numbers is divided by six,the remainder is 1 and 3 respectively..when 1 is divided by six am sure we would not get 1 as a remainder neither would we get 3 as a remainder when the integer 3 is divided by 6

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That's not correct.

  • When a smaller integer is divided by a larger integer, the quotient is 0 and the remainder is the smaller integer.
    For example, 7 divided by 11 has the quotient 0 and the remainder 7 since 7=11*0+7

Hence, 1 divided by 6 yields the remainder of 1 and 3 divided by 6 yields the remainder of 3.

For more check Remainders chapter of Math Book: remainders-144665.html
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RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: If M and N are positive integers   [#permalink] 10 Jan 2013, 03:42
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