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If m is an integer, is m odd?

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If m is an integer, is m odd? [#permalink] New post 27 Mar 2012, 03:22
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If m is an integer, is m odd?

(1) m/2 is not an even integer.
(2) m – 3 is an even integer.
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Re: If m is an integer, is m odd? [#permalink] New post 27 Mar 2012, 03:24
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \frac{m}{2}\neq{even} could occur when m is odd as well as when m is even (10 and 5 for example) --> \frac{m}{2}=\frac{10}{2}=5\neq{even} and \frac{m}{2}=\frac{5}{2}=2.5\neq{even}. Not sufficient.

(2) m-3 is an even integer --> m-odd=even --> m=even+odd=odd. Sufficient.

Answer: B.
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Re: If m is an integer, is m odd? [#permalink] New post 27 Mar 2012, 06:54
dzodzo85 wrote:
If m is an integer, is m odd?

(1) m/2 is not an even integer.
(2) m – 3 is an even integer.

Please explain this question further


can some body please explain to me why A is INSUFFICIENT

i see it this way

given that select those items which make m/2 <> even

so take
m = 6, 10, -10, -14 etc

they give 3,5,-5,-7 etc...

so m is even , so is m odd is answered in NEGATIVE.....so this is sufficient to answer the question right?

can some please explain why it is INSUFFICIENT
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Re: If m is an integer, is m odd? [#permalink] New post 27 Mar 2012, 06:58
harshavmrg wrote:
dzodzo85 wrote:
If m is an integer, is m odd?

(1) m/2 is not an even integer.
(2) m – 3 is an even integer.

Please explain this question further


can some body please explain to me why A is INSUFFICIENT

i see it this way

given that select those items which make m/2 <> even

so take
m = 6, 10, -10, -14 etc

they give 3,5,-5,-7 etc...

so m is even , so is m odd is answered in NEGATIVE.....so this is sufficient to answer the question right?

can some please explain why it is INSUFFICIENT


Please read the solution above:
For m/2 not to be an even integer m can be even (10) as well as odd (5).
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Re: If m is an integer, is m odd? [#permalink] New post 31 Mar 2012, 06:18
Bunuel wrote:
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \frac{m}{2}\neq{even} could occur when m is odd as well as when m is even (10 and 5 for example) --> \frac{m}{2}=\frac{10}{2}=5\neq{even} and \frac{m}{2}=\frac{5}{2}=2.5\neq{even}. Not sufficient.

(2) m-3 is an even integer --> m-odd=even --> m=even+odd=odd. Sufficient.

Answer: B.


Isn't \frac{m}{2} said to be an integer (though not even)? So that \frac{5}{2} is not the case.

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Re: If m is an integer, is m odd? [#permalink] New post 31 Mar 2012, 06:23
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Rigorous wrote:
Bunuel wrote:
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \frac{m}{2}\neq{even} could occur when m is odd as well as when m is even (10 and 5 for example) --> \frac{m}{2}=\frac{10}{2}=5\neq{even} and \frac{m}{2}=\frac{5}{2}=2.5\neq{even}. Not sufficient.

(2) m-3 is an even integer --> m-odd=even --> m=even+odd=odd. Sufficient.

Answer: B.


Isn't \frac{m}{2} said to be an integer (though not even)? So that \frac{5}{2} is not the case.

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Not so. (1) just says that m/2 is not an even integer, from which you can no way assume that m/2 is an odd integer, it can not be an integer at all.
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If M is an integer, is m odd? [#permalink] New post 02 Feb 2013, 11:31
(1) m/2 is not an even integer

(2) m-3 is an even integer


I was a bit confused about what statement 1 even meant to be honest. The correct answer is B (only state 2 being sufficient). Can someone help me understand what statement 1 is saying... as well as why it is insufficient? Thanks!
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Re: If M is an integer, is m odd? [#permalink] New post 02 Feb 2013, 12:12
Hi there,

m/2 is not an even integer

This means that if you divide the variable m (which represents some number) that the result will not be an even (a number divisible by 2) integer (a whole number: -1,-2,0,1,2...). So M cannot be the number 4 because 4/2 =2 which is an even integer. m could be 5 because 5/2 = 2.5 which is not an integer nor is it even. M could be 6 because 6/2 =3 which is an integer but is not even.

So the main point of this statement is that there are two possibilities for m: m is either an even number with only ONE 2 as a factor (2, 6, 14...) or m is odd. Therefore the statement is insufficient because m could be an even number or an odd number.

I hope this helps. Let me know if you need any more advise on this.

HG.
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Re: If m is an integer, is m odd? [#permalink] New post 03 Feb 2013, 10:57
For fact statement 1, take (m/2)=3,7,5 etc .. you get all values of "m" as even. So your ans to the problem statement is a NO. Now take, m/2=1.5 Thus here we see that m=odd, hence a Yes. So statement A is not sufficient.

Last edited by vinaymimani on 07 May 2013, 09:48, edited 1 time in total.
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Number Properties related question [#permalink] New post 25 Apr 2013, 19:16
Hey guys,

Can anybody explain me why the following is B?

If m is an integer, is m odd?

(1) m/2 is NOT an even integer
(2) m - 3 is an even integer.

My thought process was:

(1) Since m/2 is NOT an even integer, then => it IS an odd integer. subsequently ODD * 2 = EVEN. Sufficient

Many thanks,
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Re: Number Properties related question [#permalink] New post 25 Apr 2013, 20:46
ahatoval wrote:
Hey guys,

Can anybody explain me why the following is B?

If m is an integer, is m odd?

(1) m/2 is NOT an even integer
(2) m - 3 is an even integer.

My thought process was:

(1) Since m/2 is NOT an even integer, then => it IS an odd integer. subsequently ODD * 2 = EVEN. Sufficient

Many thanks,


Hi ahatoval, this is a common mistake the GMAT likes to exploit, so it's good to have a complete understanding of it. The key is keeping track of what must be an integer, and what doesn't have to be.

Statement 2 is correct because m has to be an integer, so any odd integer -3 (or -5 or -7) would be even. Sufficient.

You seem to be more concerned with statement 1. This statement tells us that m is an integer, but that m/2 is not an even integer. This is not the same thing as being an odd integer. Let's look at values of m/2 for different m's

m=1 --) m/2 = 0.5
m=2 --) m/2 = 1
m=3 --) m/2 = 1.5
m=4 --) m/2 = 2
...
pattern repeats

Therefore, if m/2 is not an even integer, then m=4 is excluded from the list of possibilities. This leaves m=1, m=2 and m=3. M/2 can therefore be an odd integer or a non-integer. Since we have examples of both, we cannot conclude with certainty whether m is an odd integer, it can be either 1 or 2 or 3 (or 5 or 6 or 7...)

The assumption you make that leads you down the rabbit hole on this question is that m/2 must be an integer. This is not stated in the question and easily demonstrated to be false with a few small examples. On Data Sufficiency, it's often a good idea to try a few numbers and see if you can discern a pattern.

Hope this helps!
-Ron
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Re: Number Properties related question [#permalink] New post 26 Apr 2013, 00:15
ahatoval wrote:
Hey guys,

Can anybody explain me why the following is B?

If m is an integer, is m odd?

(1) m/2 is NOT an even integer
(2) m - 3 is an even integer.

My thought process was:

(1) Since m/2 is NOT an even integer, then => it IS an odd integer. subsequently ODD * 2 = EVEN. Sufficient

Many thanks,


Merging similar topics. Please refer to the solution above and ask if anything remains unclear.
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PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!


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Re: Number Properties related question [#permalink] New post 26 Apr 2013, 05:34
VeritasPrepRon wrote:
ahatoval wrote:
Hey guys,

Can anybody explain me why the following is B?

If m is an integer, is m odd?

(1) m/2 is NOT an even integer
(2) m - 3 is an even integer.

My thought process was:

(1) Since m/2 is NOT an even integer, then => it IS an odd integer. subsequently ODD * 2 = EVEN. Sufficient

Many thanks,


Hi ahatoval, this is a common mistake the GMAT likes to exploit, so it's good to have a complete understanding of it. The key is keeping track of what must be an integer, and what doesn't have to be.

Statement 2 is correct because m has to be an integer, so any odd integer -3 (or -5 or -7) would be even. Sufficient.

You seem to be more concerned with statement 1. This statement tells us that m is an integer, but that m/2 is not an even integer. This is not the same thing as being an odd integer. Let's look at values of m/2 for different m's

m=1 --) m/2 = 0.5
m=2 --) m/2 = 1
m=3 --) m/2 = 1.5
m=4 --) m/2 = 2
...
pattern repeats

Therefore, if m/2 is not an even integer, then m=4 is excluded from the list of possibilities. This leaves m=1, m=2 and m=3. M/2 can therefore be an odd integer or a non-integer. Since we have examples of both, we cannot conclude with certainty whether m is an odd integer, it can be either 1 or 2 or 3 (or 5 or 6 or 7...)

The assumption you make that leads you down the rabbit hole on this question is that m/2 must be an integer. This is not stated in the question and easily demonstrated to be false with a few small examples. On Data Sufficiency, it's often a good idea to try a few numbers and see if you can discern a pattern.

Hope this helps!
-Ron



Thanks, Ron . :-D Totally makes sense.
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Re: If M is an integer, is m odd? [#permalink] New post 07 May 2013, 09:18
exploringm wrote:
(1) m/2 is not an even integer

(2) m-3 is an even integer


I was a bit confused about what statement 1 even meant to be honest. The correct answer is B (only state 2 being sufficient). Can someone help me understand what statement 1 is saying... as well as why it is insufficient? Thanks!


in my opinion,m/2 is not an even integer means that m/2 could be an odd integer,but also can not be an integer at all, e.g. a decimal
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Re: If M is an integer, is m odd? [#permalink] New post 07 May 2013, 09:35
fritz wrote:
exploringm wrote:
(1) m/2 is not an even integer

(2) m-3 is an even integer


I was a bit confused about what statement 1 even meant to be honest. The correct answer is B (only state 2 being sufficient). Can someone help me understand what statement 1 is saying... as well as why it is insufficient? Thanks!


in my opinion,m/2 is not an even integer means that m/2 could be an odd integer,but also can not be an integer at all, e.g. a decimal


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Re: If M is an integer, is m odd?   [#permalink] 07 May 2013, 09:35
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