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Senior Manager
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If m is an integer, is m odd? [#permalink]
 06 Nov 2005, 13:00
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53% (01:36) correct
46% (00:44) wrong based on 1 sessions
If m is an integer, is m odd? (1) m/2 is not an even integer (2) m-3 is an even integer OPEN DISCUSSION OF THIS QUESTION IS HERE: if-m-is-an-integer-is-m-odd-129702.html
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it should be B.
if m/2 is not an even integer then m can be an dd integer or a non integer.
so A is not the answer
form statement 2 m-3 is even so m must be odd.
so answer is B
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Senior Manager
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Thats correct Nakib. Good catch, I missed to consider that m/2 could be a fraction  and considered only even integers of m and choose D.
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Current Student
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Also, picking either 10 or 11 result in a non-even interger for A.
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B
St1: m could be anything except a multiple of 4. Like m = 3, m = 6: INSUFF
St2: m is an odd integer: SUFF
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Senior Manager
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(B)
I. says that m/2 can be an odd integer or even a fraction .. Insufficient
II. sufficient.
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VP
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sgrover wrote: (B)
I. says that m/2 can be an odd integer or even a fraction .. Insufficient
II. sufficient.
a fraction? but (1) say not AN EVEN INTEGER... so we can't assume that it is ODD Integer?
so 1 to me says m is integer AND m is NOT even integer... so M could be 2 or 6 or 10... it can't be 20 because it would contradict st (1) that says outcome isn't even... which makes M even  still confused...
The anwer is B, of course.
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Manager
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yes, the naswer is (B), of course. Here is how I would explain it.
ST1. m is an integer and m/2 is not an even integer
If m=2 then m/2=1 is not an even integer (Note m is even)
If m=3 then m/2=1.5 is not an even integer (Note m is odd here)
So, not sufficient
ST2. Obviously sufficient, m must be odd
(B)
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VP
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I guess the answer to my question is that if GMAT says if M isn't an even integer, it can be odd interger, a fraction or some other crazy thing 
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Re: DS: Odd/Even integer [#permalink]
31 Jul 2006, 20:24
u2lover wrote: if m is an integer, is m odd? (1) m/2 is not an even integer (2) m-3 is an even integer is (1) saying that m isn't an integer, or it isn't an even integer, or it isn't integer at all 
u2 baby, it is clearly said in the question that m is an integer. but we donot know whether it is even or odd. if it is even, m/2 is an odd integer. if it is odd, m/2 is a fraction. so m is a multiple of odd integers. but be sure that m cannot be 0 or multiples of 4.
st 2- its crystal clear.
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VP
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I know B is crystal clear... but (1) wasn't so crystal (along with the fact that M is an integer) when I tried to solve it 
sorry for the stupid questions, I really don't like DS number properties if you can't tell...
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I agree with U2lover.
IMO we make these stupid errors because of overconfidence and tryign to solve something fast.
Of course reading (1) its easy to assume that m/2 is an odd integer. But the fact remains that m/2 is not even integer. It can be a fraction hence cannot say anything about m
(2) O - E = E
Hence Suff
B is the answer.
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Senior Manager
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Priya,
m/2 is not an even integer can mean that m/2 is not even and/or m/2 is not an integer.
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Manager
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m/2 is NOT an even integer does not necessarily mean that "m/2 is an odd integer" ..........m/2 may not be an integer at all
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If m is an integer, is m odd?
1) m/2 is NOT an even integer
2) m-3 is an even integer.
from one
m/2 not even intiger
m could be a fraction or odd ......not suff
from two
m-3 = even only odd-odd = even thus m is even ....suff
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If m is an integer, is m odd?
1) m/2 is not an even integer
2) m-3 is an even integer
st one to me means :
m/2 could be odd ie 6/2 = 3 or could be a fraction 1/2 and m might be odd
3/2...........insuff
from two
m is sure odd ......suff B is my answer
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I agree, 1 is insufficient, could be even or odd. However any even number subtracted by 3 will be odd everytime.
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Senior Manager
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(1) yezz wrote: m/2 could be odd
Exactly. m/2 could be 1/2 (fraction), 2/2 (odd), 3/2(fraction), 4/2 (even)... => (1) insuff => B, C, or E.
(2) is straightfwd. m-3 = even => m = odd, always => B.
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Senior Manager
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Thanks guys. When m/2 is not an even integer, I understood it to be an odd integer. But it could be a fraction too.
m could be odd integer 3 or even integer 10 and satisfy the condition. That is what OE says.
OA B
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i'm thinking B
statement 2 shows quite clearly that m is an odd integer
For stat 1, m/2 is not an even integer, i'd interpret it as
m/2 is either an odd integer or m/2 is not an integer at all
so m/2 can be 7 or 49/2 so m can be even or odd
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