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If m is an integer such that (-2)^2m=2^(9-m) then m=?

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If m is an integer such that (-2)^2m=2^(9-m) then m=? [#permalink] New post 27 Dec 2012, 06:46
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If m is an integer such that (-2)^2m=2^(9-m) then m=?

A. 1
B. 2
C. 3
D. 5
E. 6
[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Dec 2012, 06:53, edited 1 time in total.
Renamed the topic and edited the question.
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Re: If m is an integer such that (-2)^2m=2^(9-m) then m=? [#permalink] New post 27 Dec 2012, 06:55
fozzzy wrote:
If m is an integer such that (-2)^2m=2^(9-m) then m=?

A. 1
B. 2
C. 3
D. 5
E. 6


First of all (-2)^{2m}=2^{2m}. So, we have that 2^{2m}=2^{9-m} --> 2m=9-m --> m=3.

Answer: C.
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Re: If m is an integer such that (-2)^2m=2^(9-m) then m=?   [#permalink] 27 Dec 2012, 06:55
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