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If m is divisible by 3, how many prime factors does m have?

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If m is divisible by 3, how many prime factors does m have? [#permalink] New post 26 Jan 2012, 05:36
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If m is divisible by 3, how many prime factors does m have?

(1) \(\frac{m}{3}\) is divisible by 3

(2) \(\frac{m}{3}\) has two different prime factors
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Re: Prime Factors [#permalink] New post 26 Jan 2012, 06:50
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LM wrote:
If m is divisible by 3, how many prime factors does m have?

1) \(\frac{m}{3}\) is divisible by 3

2) \(\frac{m}{3}\) has two different prime factors


If m is divisible by 3, how many prime factors does m have?

(1) \(\frac{m}{3}\) is divisible by 3 --> \(\frac{m}{3}=3k\) --> \(m=3^2*k\) --> \(m\) has at least one prime 3, but it can have more than one, in case \(k\) has some number of other primes. Not sufficient

2) \(\frac{m}{3}\) has two different prime factors --> first of all 3 is a factor of \(m\), so 3 is one of the primes of \(m\) for sure.

Now, if power of 3 in \(m\) is more than or equal to 2 then \(m\) will have have only two prime factors: 3 and one other, example: \(m=18\), (as in \(\frac{m}{3}\) one 3 will be reduced, at least one more 3 will be left, plus one other, to make the # of different factors of \(\frac{m}{3}\) equal to two. Thus \(m\) will have 3 and some other prime as a prime factors).

But if \(m\) has 3 in power of one then \(m\) will have 3 prime factors: 3 and two others, example \(m=30\) (one 3 will be reduced in \(m\) and \(\frac{m}{3}\) will have some other two prime factors, which naturally will be the primes of \(m\) as well). Not sufficient.

(1)+(2) From (1) \(3^2\) is a factor of \(m\), thus from (2) \(m\) has only two distinct prime factors: 3 and one other. Sufficient.

Answer: C.
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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 26 Mar 2013, 01:46
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LM wrote:
If m is divisible by 3, how many prime factors does m have?

1) \(\frac{m}{3}\) is divisible by 3

2) \(\frac{m}{3}\) has two different prime factors



Given:

m= 3s


Statement 1:

m = 9r

Not sufficient as r may be formed of 1 or more prime factors.


Statement 2:

m/3 = p*q

Not sufficient because p or q may be 3.

So we need to find whether p or q is 3.


Taken together:

1. Since m is divisible by 9 from statement 1, m/3 is divisible by 3.

2. From (1) above , we can say that the RHS in statement 2 is a product of 3. i.e., one of p or q is 3.

3. From (2) above, we can say that m has two different prime factors since m/3 = p*q and if say p is 3, then m=3*3*q

Therefore the answer is choice C.
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Re: Prime Factors [#permalink] New post 26 Jan 2012, 07:04
Just one thought bunuel..... The question asks for "how many prime factors". It does not ask for "how many DIFFERENT prime factors". If combined the statements tell us that \(3^2\) is a prime factor and there is a different prime factor as well, we still do not know how many times that "different" prime factor repeats. So my question is, when the question ask for number of prime factors, does it mean we should be looking at "different" prime factors or should we count the different factors each time they are repeated as well..
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Re: Prime Factors [#permalink] New post 26 Jan 2012, 07:31
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omerrauf wrote:
Just one thought bunuel..... The question asks for "how many prime factors". It does not ask for "how many DIFFERENT prime factors". If combined the statements tell us that \(3^2\) is a prime factor and there is a different prime factor as well, we still do not know how many times that "different" prime factor repeats. So my question is, when the question ask for number of prime factors, does it mean we should be looking at "different" prime factors or should we count the different factors each time they are repeated as well..


Well, the real GMAT question will ask about "distinct primes", to avoid such technicalities, though we can say that it's implied here.
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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 25 Mar 2013, 19:52
Hi Bunuel,

I answer B, since statement 2 says it has 2 different primes factor (3 included for sure) answering directly to the question. Why (2) it's insufficient? I didn't understand your approach, please explain. Thanks!
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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 26 Mar 2013, 00:40
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marcovg4 wrote:
Hi Bunuel,

I answer B, since statement 2 says it has 2 different primes factor (3 included for sure) answering directly to the question. Why (2) it's insufficient? I didn't understand your approach, please explain. Thanks!


The second statement says that m/3 has two different prime factors, NOT m.

If m = 18, then m/3 = 6 (6 has two different prime factors: 2, and 3). 18 has two different prime factors 2 and 3.
If m = 30, then m/3 = 10 (10 has two different prime factors: 2, and 5). 30 has three different prime factors 2, 3 and 5.

Thus this statement is NOT sufficient.

Does this make sense?
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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 26 Mar 2013, 05:26
Yes Bunuel, thanks!

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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 27 Mar 2013, 15:59
@Bunuel

second statement says m has two different prime factors. Can it be taken as it has only 2 different prime factors? if m/3 is 42, the second statement is still true!?
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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 28 Mar 2013, 02:58
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Re: Prime Factors [#permalink] New post 30 Mar 2013, 03:56
Bunuel wrote:
LM wrote:
If m is divisible by 3, how many prime factors does m have?

1) \(\frac{m}{3}\) is divisible by 3

2) \(\frac{m}{3}\) has two different prime factors


If m is divisible by 3, how many prime factors does m have?

(1) \(\frac{m}{3}\) is divisible by 3 --> \(\frac{m}{3}=3k\) --> \(m=3^2*k\) --> \(m\) has at least one prime 3, but it can have more than one, in case \(k\) has some number of other primes. Not sufficient

2) \(\frac{m}{3}\) has two different prime factors --> first of all 3 is a factor of \(m\), so 3 is one of the primes of \(m\) for sure.

Now, if power of 3 in \(m\) is more than or equal to 2 then \(m\) will have have only two prime factors: 3 and one other, example: \(m=18\), (as in \(\frac{m}{3}\) one 3 will be reduced, at least one more 3 will be left, plus one other, to make the # of different factors of \(\frac{m}{3}\) equal to two. Thus \(m\) will have 3 and some other prime as a prime factors).

But if \(m\) has 3 in power of one then \(m\) will have 3 prime factors: 3 and two others, example \(m=30\) (one 3 will be reduced in \(m\) and \(\frac{m}{3}\) will have some other two prime factors, which naturally will be the primes of \(m\) as well). Not sufficient.

(1)+(2) From (1) \(3^2\) is a factor of \(m\), thus from (2) \(m\) has only two distinct prime factors: 3 and one other. Sufficient.

Answer: C.


Hi Bunnel,

Can you please explain me the statement.

(1)+(2) From (1) \(3^2\) is a factor of \(m\), thus from (2) \(m\) has only two distinct prime factors: 3 and one other. Sufficient.

I didn't get how you got the answer after combing the two
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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 18 Feb 2014, 05:12
My way:

First of all we are told that m = 3k where 'k' is an integer. How many different prime factors does 'm' have?

Statement 1: m = 9k, nothing about prime factors
Statement 2: m/3 has two different prime factors. Well if m = 3k then 3k/3 = k has two different prime factors but no info on 'm' yet. 'k' could have 3 among its factors or not. Therefore since we are asked about different prime factors then this statement alone is not sufficient.

Statements 1 and 2 together tell us that 9k/3=3k has two different prime factors. Since m = 3k then it must be that 'k' is another different prime factors Therefore C is our answer

Hope this helps
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Re: If m is divisible by 3, how many prime factors does m have? [#permalink] New post 15 Sep 2015, 22:41
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Re: If m is divisible by 3, how many prime factors does m have?   [#permalink] 15 Sep 2015, 22:41
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