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If m<n and a<b, then a. (m+a)<n-b b.

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If m[#permalink] New post 07 Mar 2004, 12:35
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If m<n and a<b, then

a. (m+a)<n-b
b. (m+a)<n+b
c. (ma)<nb
d. (m/a)<n/b
e. :evil:
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 [#permalink] New post 07 Mar 2004, 12:44
I believe B is the answer.

a) not satisfied.
Let m = 1 n = 2 a = 1 b = 2
m+a = 2 n-b = 0

b) satisfied
for all +ve values
for all -ve values

c) not satisfied
m = -2 n = 1 a = -2 b = 1
mn = 4 ab = 1

d) not satisfied
m = -2 n = 1 a = -2 b = 1
m/a = 1 n/b = 1
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 [#permalink] New post 07 Mar 2004, 12:54
anand,
your right.
What I would like to know is what made you choose the plug-in figures that you had chosen to test for validity?
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Pls include reasoning along with all answer posts.
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Este examen me conduce jodiendo loco

  [#permalink] 07 Mar 2004, 12:54
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If m<n and a<b, then a. (m+a)<n-b b.

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