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# If m & n are integers, is m odd? 1.) n+m is odd 2.) n+m

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Director
Joined: 11 Sep 2006
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If m & n are integers, is m odd? 1.) n+m is odd 2.) n+m [#permalink]  16 Oct 2006, 18:46
If m & n are integers, is m odd?

1.) n+m is odd
2.) n+m = n^2 +5
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Manager
Joined: 07 Jun 2006
Posts: 113
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B

A: if n is odd, m is even else its odd. INSUFF

B: Can be written as m= n(n-1)+5
= odd * even + odd (N being odd or even)
= even + odd
= odd SUFF
Director
Joined: 17 Jul 2006
Posts: 716
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Kudos [?]: 9 [0], given: 0

girikorat wrote:
B

A: if n is odd, m is even else its odd. INSUFF

B: Can be written as m= n(n-1)+5
= odd * even + odd (N being odd or even)
= even + odd
= odd SUFF

Yes B is sufficient.
Senior Manager
Joined: 30 Aug 2006
Posts: 374
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Yep B

If m & n are integers, is m odd?

1.) n+m is odd
2.) n+m = n^2 +5

I) one is odd one is even, could be either INS
II) if n is odd n^2 = odd, then it would be odd+odd = even
if n is even then n^2 = even so it would be even + odd = odd

n must be even and m must be odd

SUFF
Director
Joined: 23 Jun 2005
Posts: 847
GMAT 1: 740 Q48 V42
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Kudos [?]: 36 [0], given: 1

B

Statement 1:
m = odd, only if n = even INSUFF

Statement 2:
n+m = n*n +5

If n = odd, then n+m = even, which makes m = odd
If n = even, then n+m = odd, which makes m = odd SUFF
Senior Manager
Joined: 13 Sep 2006
Posts: 282
Location: New York
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Yes - B is sufficient. Try picking numbers. M cannot be even.

n+m=n^2+5 tells you that m& n are either both odd or one is odd or even. regardless m will be odd.
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