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If m & n are integers, is m odd? 1.) n+m is odd 2.) n+m

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Director
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If m & n are integers, is m odd? 1.) n+m is odd 2.) n+m [#permalink] New post 16 Oct 2006, 18:46
If m & n are integers, is m odd?

1.) n+m is odd
2.) n+m = n^2 +5
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 [#permalink] New post 16 Oct 2006, 19:52
B

A: if n is odd, m is even else its odd. INSUFF

B: Can be written as m= n(n-1)+5
= odd * even + odd (N being odd or even)
= even + odd
= odd SUFF
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 [#permalink] New post 16 Oct 2006, 21:28
girikorat wrote:
B

A: if n is odd, m is even else its odd. INSUFF

B: Can be written as m= n(n-1)+5
= odd * even + odd (N being odd or even)
= even + odd
= odd SUFF


Yes B is sufficient.
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 [#permalink] New post 17 Oct 2006, 01:44
Yep B

If m & n are integers, is m odd?

1.) n+m is odd
2.) n+m = n^2 +5

I) one is odd one is even, could be either INS
II) if n is odd n^2 = odd, then it would be odd+odd = even
if n is even then n^2 = even so it would be even + odd = odd

n must be even and m must be odd

SUFF
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 [#permalink] New post 17 Oct 2006, 18:34
B

Statement 1:
m = odd, only if n = even INSUFF

Statement 2:
n+m = n*n +5

If n = odd, then n+m = even, which makes m = odd
If n = even, then n+m = odd, which makes m = odd SUFF
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 [#permalink] New post 18 Oct 2006, 06:29
Yes - B is sufficient. Try picking numbers. M cannot be even.


n+m=n^2+5 tells you that m& n are either both odd or one is odd or even. regardless m will be odd.
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  [#permalink] 18 Oct 2006, 06:29
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If m & n are integers, is m odd? 1.) n+m is odd 2.) n+m

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