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If M = sqrt of 4 + cube root of 4 + quad root of 4, M = ?

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Manager
Joined: 04 Apr 2007
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If M = sqrt of 4 + cube root of 4 + quad root of 4, M = ?  [#permalink]  13 Apr 2007, 20:13
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If M = sqrt of 4 + cube root of 4 + quad root of 4, M = ?

less than 3
equal to 3
between 3 and 4
equal to 4
greater than 4

Ok, I'm just getting bungled with all the exponents rules. There is no way to combine these terms under the same base of 4 is there? Ugh!
Director
Joined: 14 Jan 2007
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[#permalink]  14 Apr 2007, 03:51
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KUDOS
M = sqrt of 4 + cube root of 4 + quad root of 4
No need to calculate ...
Sqrt of 4 = 2
Cube root of 4 should be > 1
Quad root of 4 should be > 1
Hence M should be > 4

The rule is nth root of any positive integer >1, will be always be > 1
Senior Manager
Joined: 01 Jan 2007
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[#permalink]  14 Apr 2007, 04:27
thats right i absolutely agree. M must be greater than 4

Javed.

Cheers!
Manager
Joined: 04 Apr 2007
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Kudos [?]: 6 [0], given: 0

[#permalink]  14 Apr 2007, 07:12
Thanks vshaunak! My brain goes blank at times and I end up making many questions harder than they should be
[#permalink] 14 Apr 2007, 07:12
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If M = sqrt of 4 + cube root of 4 + quad root of 4, M = ?

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