If machine X ran continuously at a uniform rate to fill

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If machine X ran continuously at a uniform rate to fill [#permalink]

15 Mar 2012, 02:06

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If machine X ran continuously at a uniform rate to fill a production order, at what time did the machine finish filling the order?

(1) Machine X had filled 2/3 of the order by 10:00 a.m. and 5/6 of the order by 10:30 a.m.
(2) Machine X had filed 1/6 of the order by 8:30 a.m. and 1/3 of the order by 9:00 a.m.

How come statement B is sufficient?

As far as statement 1 is concerned:

Machine completed (5/6 - 2/3 = 1/6) of the order in half an hour. As the question says that the rate is constant and since at 10:30 it has 1/6 of the order remaining to fill, it will take another half an hour and finish filling the order at 11:00. Therefore, this statement is sufficient.

How come B is sufficient?

[Reveal] Spoiler: OA

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Re: Machine X [#permalink]

15 Mar 2012, 02:38

enigma123 wrote:

If machine X ran continuously at a uniform rate to fill a production order, at what time did the machine finish filling the order?
(1) Machine X had filled 2/3 of the order by 10:00 a.m. and 5/6 of the order by 10:30 a.m.
(2) Machine X had lled 1/6 of the order by 8:30 a.m. and 1/3 of the order by 9:00 a.m.

How come statement B is sufficient?

As far as statement 1 is concerned:

Machine completed (5/6 - 2/3 = 1/6) of the order in half an hour. As the question says that the rate is constant and since at 10:30 it has 1/6 of the order remaining to fill, it will take another half an hour and finish filling the order at 11:00. Therefore, this statement is sufficient.

How come B is sufficient?

If machine X ran continuously at a uniform rate to fill a production order, at what time did the machine finish filling the order?

(1) Machine X had filled 2/3 of the order by 10:00 a.m. and 5/6 of the order by 10:30 a.m. --> between 10:00 a.m. and 10:30 a.m. machine X completed 5/6-2/3=1/6 of the job in half an hour, also 1-5/6=1/6 part of the job is left to complete, so another half an hour is needed. Machine X will finish filling the order at 10:30 a.m. + 30 min = 11:00 a.m. Sufficient.

(2) Machine X had filled 1/6 of the order by 8:30 a.m. and 1/3 of the order by 9:00 a.m. --> the same way here: in 9:00 a.m.-8:30 a.m=30 minutes machine X completed 1/3-1/6=1/6 of the job, also 1-1/3=4/6 part of the job is left to complete, so another 4*30=2 hours are needed. Machine X will finish filling the order at 9:00 a.m. + 2 hours = 11:00 a.m. Sufficient.

Answer: D.
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Re: Machine X [#permalink] 15 Mar 2012, 02:38

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If machine X ran continuously at a uniform rate to fill

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If machine X ran continuously at a uniform rate to fill

If machine X ran continuously at a uniform rate to fill

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