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If machine X ran continuously at a uniform rate to fill

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If machine X ran continuously at a uniform rate to fill [#permalink]

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New post 15 Mar 2012, 02:06
00:00
A
B
C
D
E

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88% (01:42) correct 12% (00:35) wrong based on 139 sessions

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If machine X ran continuously at a uniform rate to fill a production order, at what time did the machine finish filling the order?

(1) Machine X had …filled 2/3 of the order by 10:00 a.m. and 5/6 of the order by 10:30 a.m.
(2) Machine X had …filed 1/6 of the order by 8:30 a.m. and 1/3 of the order by 9:00 a.m.

[Reveal] Spoiler:
How come statement B is sufficient?

As far as statement 1 is concerned:

Machine completed (5/6 - 2/3 = 1/6) of the order in half an hour. As the question says that the rate is constant and since at 10:30 it has 1/6 of the order remaining to fill, it will take another half an hour and finish filling the order at 11:00. Therefore, this statement is sufficient.

How come B is sufficient?
[Reveal] Spoiler: OA

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Re: Machine X [#permalink]

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New post 15 Mar 2012, 02:38
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If machine X ran continuously at a uniform rate to fill a production order, at what time did the machine finish filling the order?

(1) Machine X had …filled 2/3 of the order by 10:00 a.m. and 5/6 of the order by 10:30 a.m. --> between 10:00 a.m. and 10:30 a.m. machine X completed 5/6-2/3=1/6 of the job in half an hour, also 1-5/6=1/6 part of the job is left to complete, so another half an hour is needed. Machine X will finish filling the order at 10:30 a.m. + 30 min = 11:00 a.m. Sufficient.

(2) Machine X had …filled 1/6 of the order by 8:30 a.m. and 1/3 of the order by 9:00 a.m. --> the same way here: in 9:00 a.m.-8:30 a.m=30 minutes machine X completed 1/3-1/6=1/6 of the job, also 1-1/3=4/6 part of the job is left to complete, so another 4*30=2 hours are needed. Machine X will finish filling the order at 9:00 a.m. + 2 hours = 11:00 a.m. Sufficient.

Answer: D.
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Re: If machine X ran continuously at a uniform rate to fill [#permalink]

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New post 16 Jun 2016, 21:07
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Re: If machine X ran continuously at a uniform rate to fill [#permalink]

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New post 16 Jun 2016, 22:58
enigma123 wrote:
If machine X ran continuously at a uniform rate to fill a production order, at what time did the machine finish filling the order?

(1) Machine X had …filled 2/3 of the order by 10:00 a.m. and 5/6 of the order by 10:30 a.m.
(2) Machine X had …filed 1/6 of the order by 8:30 a.m. and 1/3 of the order by 9:00 a.m.




Statement 1.

Machine X completes (2/3) of order by 10 am and 5/6 of order by 10:30 am.

so (4/6) order is completed by 10 am and (5/6) of order is completed by 10:30 am.

Machine X completes\((\frac{5}{6}-\frac{4}{6})\) = \(\frac{1}{6}\) order in (1/2) hour.
Rate of machine X is known.

We know that at 10:30 (1/6) of the order is remaining. This remainign order will be completed in next half an hour i.e. 11 am.

A is sufficient.


Statement 2

Machine X completes (2/3) of order by 10 am and 5/6 of order by 10:30 am.

so (4/6) order is completed by 10 am and (5/6) of order is completed by 10:30 am.

Machine X completes\((\frac{5}{6}-\frac{4}{6})\) = \(\frac{1}{6}\) order in (1/2) hour.
Rate of machine X is known.

We know that at 10:30 (1/6) of the order is remaining. This remaining order will be completed in next half an hour i.e. 11 am.

(1) is sufficient.

Machine X had …filed 1/6 of the order by 8:30 a.m. and 2/6 of the order by 9:00 a.m
so once again

Machine X completes\((\frac{2}{6}-\frac{1}{6})\) = \(\frac{1}{6}\) order in (1/2) hour.
Rate of Machine X is known

At 9 am (4/6) order remains.
Order can be completed in 2 hours.

(2) is sufficient.
Re: If machine X ran continuously at a uniform rate to fill   [#permalink] 16 Jun 2016, 22:58
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