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If mv < pv < 0, is v>0? 1) m < p 2) m < 0

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Manager
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If mv < pv < 0, is v>0? 1) m < p 2) m < 0 [#permalink] New post 20 Dec 2006, 05:14
If mv < pv < 0, is v>0?

1) m < p
2) m < 0
Manager
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Re: GMATPREP: V>0? [#permalink] New post 20 Dec 2006, 06:41
lfox2 wrote:
If mv < pv < 0, is v>0?

1) m < p
2) m < 0


B

Stmt 1)m<p so v can be + or - Not sufficient

Stmt2) if m<0 v must be greater than o for mv and pv to be less than o
So sufficient
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Re: GMATPREP: V>0? [#permalink] New post 20 Dec 2006, 06:56
lfox2 wrote:
If mv < pv < 0, is v>0?

1) m < p
2) m < 0

I get D

mv < pv < 0

=> v(p-m) < 0

=> ( p-m <0 and v >0) or (v < 0 and p-m >0)

1) m<p => p-m >0 =>v < 0

2) m <0
Given mv < 0 => v > 0.
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 [#permalink] New post 20 Dec 2006, 07:41
I get D too...both are essentially telling you the same thing. Because M<P, both are negative numbers and V is positive b/c if M and P were positive then pv<mv...
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 [#permalink] New post 20 Dec 2006, 16:24
my answer is D

question gives: mv < pv < 0
question asks : v > 0 ?


(1) m < p
-------------
if V is -ive: both m and p must be +ive
but if m < p --> mv > pv, contradicts the given relation in the question

So, V must be +ive
Statement 1 is sufficient

(2) m < 0
------------
if m is -ive --> v must be +ive such that mv will be -ive [ mv < 0 ] as given in the question
So, V must be +ive
Statement 2 is sufficient

Answer: D
  [#permalink] 20 Dec 2006, 16:24
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