If mv < pv< 0, is v > 0?

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If mv < pv< 0, is v > 0? [#permalink]

20 May 2012, 14:14

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If mv < pv< 0, is v > 0?

(1) m < p
(2) m < 0

[Reveal] Spoiler: OA

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Re: Is v positive? [#permalink]

20 May 2012, 18:18

Note that both mv and pv are negative.

Statement 1: m<p
=> mv<pv if v is positive (and is given to us)
=> mv>pv is v is negative

Therefore v is positive. Sufficient.

Statement 2: m<0
=> mv<0 only if v is positive (and this is given to us)

Therefore v is positive.

Sufficient.

D it is.
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Re: If mv < pv< 0, is v > 0? [#permalink]

21 May 2012, 01:17

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If mv < pv< 0, is v > 0?

Given: mv<pv<0 --> two cases:

If v>0 then when dividing by v we would have: m<p<0;
If v<0 then when dividing by v we would have: m>p>0 (flip the sign when dividing by negative value).

(1) m < p --> we have the first case, so v>0. Sufficient.
(2) m < 0 --> we have the first case, so v>0. Sufficient.

Answer: D.

Hope it's clear.
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Re: If mv < pv< 0, is v > 0? [#permalink]

23 May 2012, 02:49

If mv < pv< 0, is v > 0?
from here, we know that:
mv < 0 -> if m is +, V must be -, if m is - then v is + (they must be opposite to be negative)
pv < 0 -> if p is +, V must be - ,if p is -, then v is + (they must be opposite to be negative)
mv < pv -> if v is +, then m < p,if v is - then m > p (divide both side by v,dont forget to flip inequality sign when v is -)

(1) m < p --> so v>0. Sufficient.
(2) m < 0 --> so v>0. Sufficient.

Re: If mv < pv< 0, is v > 0? [#permalink] 23 May 2012, 02:49

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If mv < pv< 0, is v > 0?

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