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# If n and k are positive integers, is n divisible by 6? (1) n

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If n and k are positive integers, is n divisible by 6? (1) n [#permalink]  12 May 2006, 10:54
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If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)
(2) k â€“ 1 is a multiple of 3.
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I think its A.
1 is sufficient bcoz, in three consecutive numbers atleast one will be even (so multiple of 2) and atleast 1 will be multiple of 3. So it's sufficient.
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(2) is sufficient too.

if k-1 is odd, then k is even, so (k-1)*k*(k+1) is divisible by 6.
if k-1 is even, then it already is divisible by 6.
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Agree with D. (Both are sufficient.)
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mendiratta_1812 wrote:
Agree with D. (Both are sufficient.)

Nope. Second Statement does not define any relationship between n and k!! Be careful.. While evaluating the second statement, forget everything that you know from first statement.
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I think my mind stops working at 2 a.m. Thank god, GMAT is not at night.

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If A equals success, then the formula is: A = X + Y + Z, X is work. Y is play. Z is keep your mouth shut.
Albert Einstein

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Got egg all over my face.
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Picking number theory here.

A alone is sufficient.

B gives no information concerning n.

OA is A
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