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I agree with the OA - the answer is C - both statements are required - for S1, if k is 1, then it doesn't hold true, S2 doesn't hold good by itself - so with S1 and S2 we can say that n is divisible by 6 - even with the statement that n is a positive integer. Any other logic?

This is besides the point, but Why in the world do you guys think if k=1, then n is not divisible by 6? If k=1, then n=0 0 is divisible by any number. Am I missing something here?

I agree with the OA - the answer is C - both statements are required - for S1, if k is 1, then it doesn't hold true, S2 doesn't hold good by itself - so with S1 and S2 we can say that n is divisible by 6 - even with the statement that n is a positive integer. Any other logic?

if K=1 then n=0..for argument sake 0/6 is divisble by 6..

If that is the logic, then 0 is divisible by all numbers - that is besides the point - I still say the OA is correct - otherwise it is a trial question meant to confuse people. Anyways we can continue with the argument. Quick question - 0 is not counted as a positive integer - if we say k not equal to 1, then we can conclude that S1 is sufficient

If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)

(2) k is not equal to 1, is a multiple of 3.

What are u guys thinking Stat 1 is clearly sufficient

n and k are positive integers

n and k cannot be zero

so in statement if u think of taking k as 1 then n=0 and 0 is not positive(see the line in red) So according to the given details k has to be greater than 1

so stat 1 is suff

now lets see that second stat

k is not equal to 1, is a multiple of 3

as every second number is even and every third number is a multiple of 3 this is also correct

I get A as well. Durgesh makes a good point that you cannot take anything you've learned in (1) when you process (2).

The only way I could see C working is if it said that n and k were non-negative integers.... Positive integers, by definition, cannot include zero. _________________

This is besides the point, but Why in the world do you guys think if k=1, then n is not divisible by 6? If k=1, then n=0 0 is divisible by any number. Am I missing something here?

BTW, I got A. I don't agree with the OA.

This was my argument as well. This question sucks.

If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1) (2) k is not equal to 1, "xxx" is a multiple of 3.

is something missing in st 2 after "k is not equal to 1," ?

from the question stem, it is clear that n and k are +ve.

1 says n is multiple of 3 +ve consecutive integer. any 3 +ve (in fact any -ve as well) consecutive integers are evenly divisible by 6. so n is divisible by 6. suff..

2 says k is an integer >1 but it has nothing to do with n. so insuff...

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