If n and k are positive integers, is n divisible by 6? (1) n : DS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 19 Jan 2017, 19:45

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If n and k are positive integers, is n divisible by 6? (1) n

Author Message
Intern
Joined: 25 May 2008
Posts: 40
Followers: 0

Kudos [?]: 5 [0], given: 0

If n and k are positive integers, is n divisible by 6? (1) n [#permalink]

Show Tags

29 May 2008, 12:31
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)

(2) k is not equal to 1, is a multiple of 3.
SVP
Joined: 28 Dec 2005
Posts: 1575
Followers: 3

Kudos [?]: 147 [0], given: 2

Show Tags

29 May 2008, 13:11
ah, good point. then it should be C
Director
Joined: 14 Jan 2007
Posts: 777
Followers: 2

Kudos [?]: 136 [0], given: 0

Show Tags

29 May 2008, 16:04
Should be 'A'.
K can't be 1 as n is a positive int.
Current Student
Joined: 28 Dec 2004
Posts: 3384
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 15

Kudos [?]: 282 [0], given: 2

Show Tags

29 May 2008, 16:07
kapilnegi wrote:
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)

(2) k is not equal to 1, is a multiple of 3.

i get D..

n= try any number..works..

even if k=1..n=0 which is divisible by 6..however n is positive so K cant be 1..

2) k=3M then K+1 will be an even number therefore N is divisible by 6..

whats the OA?
Intern
Joined: 25 May 2008
Posts: 40
Followers: 0

Kudos [?]: 5 [0], given: 0

Show Tags

29 May 2008, 19:28
Given : n and k are positive integers.

OA is C
Current Student
Joined: 28 Dec 2004
Posts: 3384
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 15

Kudos [?]: 282 [0], given: 2

Show Tags

29 May 2008, 20:02
kapilnegi wrote:
Given : n and k are positive integers.

OA is C

i cant agree with the OA..

whats the source?
Manager
Joined: 19 May 2008
Posts: 165
Location: Mumbai
Followers: 1

Kudos [?]: 11 [0], given: 0

Show Tags

29 May 2008, 20:27
I agree with the OA - the answer is C - both statements are required - for S1, if k is 1, then it doesn't hold true, S2 doesn't hold good by itself - so with S1 and S2 we can say that n is divisible by 6 - even with the statement that n is a positive integer. Any other logic?
VP
Joined: 10 Jun 2007
Posts: 1459
Followers: 7

Kudos [?]: 255 [0], given: 0

Show Tags

29 May 2008, 20:36
This is besides the point, but
Why in the world do you guys think if k=1, then n is not divisible by 6?
If k=1, then n=0
0 is divisible by any number.
Am I missing something here?

BTW, I got A. I don't agree with the OA.
Current Student
Joined: 28 Dec 2004
Posts: 3384
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 15

Kudos [?]: 282 [0], given: 2

Show Tags

29 May 2008, 20:37
tharunv wrote:
I agree with the OA - the answer is C - both statements are required - for S1, if k is 1, then it doesn't hold true, S2 doesn't hold good by itself - so with S1 and S2 we can say that n is divisible by 6 - even with the statement that n is a positive integer. Any other logic?

if K=1 then n=0..for argument sake 0/6 is divisble by 6..
Manager
Joined: 19 May 2008
Posts: 165
Location: Mumbai
Followers: 1

Kudos [?]: 11 [0], given: 0

Show Tags

29 May 2008, 20:45
If that is the logic, then 0 is divisible by all numbers - that is besides the point - I still say the OA is correct - otherwise it is a trial question meant to confuse people. Anyways we can continue with the argument. Quick question - 0 is not counted as a positive integer - if we say k not equal to 1, then we can conclude that S1 is sufficient
Manager
Joined: 10 Mar 2008
Posts: 67
Followers: 2

Kudos [?]: 32 [0], given: 0

Show Tags

29 May 2008, 21:37
kapilnegi wrote:
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)

(2) k is not equal to 1, is a multiple of 3.

What are u guys thinking
Stat 1 is clearly sufficient

n and k are positive integers

n and k cannot be zero

so in statement if u think of taking k as 1 then n=0 and 0 is not positive(see the line in red) So according to the given details k has to be greater than 1

so stat 1 is suff

now lets see that second stat

k is not equal to 1, is a multiple of 3

as every second number is even and every third number is a multiple of 3 this is also correct

so according to me ans is d
Director
Joined: 27 May 2008
Posts: 549
Followers: 8

Kudos [?]: 312 [0], given: 0

Show Tags

30 May 2008, 03:56
rohit929: statement 2 doesn tell anything about n, how can it be suff. Remember when your are reading statement 2, forget about 1.

I'll go with A.
Intern
Joined: 07 May 2008
Posts: 19
Followers: 0

Kudos [?]: 1 [0], given: 0

Show Tags

30 May 2008, 04:17
I get A as well. Durgesh makes a good point that you cannot take anything you've learned in (1) when you process (2).

The only way I could see C working is if it said that n and k were non-negative integers.... Positive integers, by definition, cannot include zero.
_________________

Ryan S.
| GMAT Instructor |
Elite GMAT Preparation and Admissions Consulting
http://www.VeritasPrep.com

CEO
Joined: 29 Mar 2007
Posts: 2583
Followers: 19

Kudos [?]: 421 [0], given: 0

Show Tags

30 May 2008, 07:37
bkk145 wrote:
This is besides the point, but
Why in the world do you guys think if k=1, then n is not divisible by 6?
If k=1, then n=0
0 is divisible by any number.
Am I missing something here?

BTW, I got A. I don't agree with the OA.

This was my argument as well. This question sucks.
Manager
Joined: 10 Mar 2008
Posts: 67
Followers: 2

Kudos [?]: 32 [0], given: 0

Show Tags

31 May 2008, 06:04
VPRedSoxFan wrote:
I get A as well. Durgesh makes a good point that you cannot take anything you've learned in (1) when you process (2).

The only way I could see C working is if it said that n and k were non-negative integers.... Positive integers, by definition, cannot include zero.

Durgesh and VPRedSoxFan n and k are positive are given in th sten not in statement 1
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)

(2) k is not equal to 1, is a multiple of 3.
SVP
Joined: 29 Aug 2007
Posts: 2492
Followers: 67

Kudos [?]: 734 [0], given: 19

Show Tags

31 May 2008, 11:10
kapilnegi wrote:
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)
(2) k is not equal to 1, "xxx" is a multiple of 3.

is something missing in st 2 after "k is not equal to 1," ?

from the question stem, it is clear that n and k are +ve.

1 says n is multiple of 3 +ve consecutive integer. any 3 +ve (in fact any -ve as well) consecutive integers are evenly divisible by 6. so n is divisible by 6. suff..

2 says k is an integer >1 but it has nothing to do with n. so insuff...

therefore, A.
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Re: DS - Integers   [#permalink] 31 May 2008, 11:10
Display posts from previous: Sort by