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If n and k are positive integers, is n divisible by 6?

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If n and k are positive integers, is n divisible by 6? [#permalink] New post 27 Aug 2009, 16:15
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A
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61% (01:45) correct 38% (00:34) wrong based on 21 sessions
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)

(2) k – 1 is a multiple of 3
[Reveal] Spoiler: OA
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Re: Is n divisible by 6? [#permalink] New post 27 Aug 2009, 16:22
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1.) Sufficient

Always remember, when 3 consecutive integers are multiplied, then one should be a multiple of 3 and atleast one (or max 2) number is even. Also, if the multiple of 3 is also the even number like 6, 12, 18 then it is divisible by 6 always..

For ex:- 1*2*3 ; -4*-5*-6 ; 4*5*6 ; 11*12*13..


In any case; the product would be divisible by 6.

2.) insufficient.. does not say anything about n..

Ans. A
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Re: Is n divisible by 6? [#permalink] New post 27 Aug 2009, 20:47
tarek99 wrote:
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)
(2) k – 1 is a multiple of 3

Please explain your answer.
Thanks


My answer would be A.
Since n = product of 3 consecutive numbers, it will be divisible by 3. We should also remember that 0 is also a multiple of 6. For eg : if k = 1,
n = 1*2*0 => n = 0 which IS divisible by 6.

I hope I am right. "0 is divisible by any number" right?
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Re: Is n divisible by 6? [#permalink] New post 27 Aug 2009, 22:50
(1) n = k(k + 1)(k - 1) --- Sufficient
(2) k – 1 is a multiple of 3 --- insufficient
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Re: Is n divisible by 6? [#permalink] New post 28 Aug 2009, 02:30
bhanushalinikhil wrote:
tarek99 wrote:
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)
(2) k – 1 is a multiple of 3

Please explain your answer.
Thanks


My answer would be A.
Since n = product of 3 consecutive numbers, it will be divisible by 3. We should also remember that 0 is also a multiple of 6. For eg : if k = 1,
n = 1*2*0 => n = 0 which IS divisible by 6.

I hope I am right. "0 is divisible by any number" right?


I slightly differ on your explination......specially if k = 1...

If k = 1 then n = 0*1*2 then n = 0 ... zero is not a positive integer hence all values of k will start from 2 onwards
hence values of n will start from 6 onwards.....but yes your ans is right A it is
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Re: Is n divisible by 6? [#permalink] New post 28 Aug 2009, 03:35
bhushan252 wrote:
bhanushalinikhil wrote:
tarek99 wrote:
If n and k are positive integers, is n divisible by 6?

(1) n = k(k + 1)(k - 1)
(2) k – 1 is a multiple of 3

Please explain your answer.
Thanks


My answer would be A.
Since n = product of 3 consecutive numbers, it will be divisible by 3. We should also remember that 0 is also a multiple of 6. For eg : if k = 1,
n = 1*2*0 => n = 0 which IS divisible by 6.

I hope I am right. "0 is divisible by any number" right?


I slightly differ on your explination......specially if k = 1...

If k = 1 then n = 0*1*2 then n = 0 ... zero is not a positive integer hence all values of k will start from 2 onwards
hence values of n will start from 6 onwards.....but yes your ans is right A it is


Right. Now see the mistake.
Thanks!
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Re: Is n divisible by 6? [#permalink] New post 15 Apr 2014, 06:54
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Re: Is n divisible by 6?   [#permalink] 15 Apr 2014, 06:54
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If n and k are positive integers, is n divisible by 6?

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