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if n and k are positive integers, is sqrt. of

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if n and k are positive integers, is sqrt. of [#permalink] New post 10 Sep 2006, 12:03
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if n and k are positive integers, is sqrt. of (n+k)>2sqrt.of n?

k>3n
n+k>3n
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Re: DS- n & k [#permalink] New post 10 Sep 2006, 12:46
lan583 wrote:
if n and k are positive integers, is sqrt. of (n+k)>2sqrt.of n?

k>3n
n+k>3n


A should be it...

From 1, k > 3n, adding n to both sides
k+n > 3n+n
k+n>4n

Taking sqrt, sqrt(k+n) > 2sqrt(n)
SUFF

From 2, n+k>3n, taking sqrt, sqrt(n+k) > sqrt(3n) which is INSUFF since
sqrt(3n) < sqrt(n+k) < 2*sqrt(n)
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 [#permalink] New post 11 Sep 2006, 01:31
if n and k are positive integers, is sqrt. of (n+k)>2sqrt.of n?

1)k>3n
2) n+k>3n

square both sides

n+k>4n.....ie k>3n

from one ...needless to say anything......suff

from two

k>2n we can never deduct that k>3n....insuff

thus A is my answer
  [#permalink] 11 Sep 2006, 01:31
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