If n and p are integers, is p>0? 1. n+1 > 0 2. np>0 : DS Archive
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# If n and p are integers, is p>0? 1. n+1 > 0 2. np>0

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If n and p are integers, is p>0? 1. n+1 > 0 2. np>0 [#permalink]

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08 Sep 2007, 18:24
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If n and p are integers, is p>0?

1. n+1 > 0
2. np>0
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Joined: 05 Mar 2007
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Re: Gmat Prep - DS [#permalink]

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09 Sep 2007, 09:38
mbunny wrote:
If n and p are integers, is p>0?

1. n+1 > 0
2. np>0

C it is

From 1) n > -1 , so n >=0, But dont know anything about p, so InSuff

From 2) np both must either be positive or both must be -ve, so p could be positive or negative

From 1) & 2) n>=0, and np>0, so, n canot be 0, and must p>0.
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09 Sep 2007, 10:53
Agree

I didnot take into account that np>0
I see the point

Ans: C

Last edited by Ferihere on 09 Sep 2007, 11:26, edited 1 time in total.
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Re: Gmat Prep - DS [#permalink]

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09 Sep 2007, 10:58
mbunny wrote:
If n and p are integers, is p>0?

1. n+1 > 0
2. np>0

I think it's C here

(1) Clearly INSUFFICIENT
(2) if n<0 and p<0, then np>0
of n>0, p>0, then np>0
INSUFFICIENT

Together, you know from (1) that
n > -1
Since n is an integer, possible values of n are: 0, 1, 2, 3, ...
Knowing that np > 0, n and P cannot be zero. This means that n can only be positive number. This also means that p is positive.
SUFFICIENT
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09 Sep 2007, 16:37
Thanks all, the OA is C.
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Re: Gmat Prep - DS [#permalink]

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09 Sep 2007, 20:08
mbunny wrote:
If n and p are integers, is p>0?

1. n+1 > 0
2. np>0

S1: nothing about p is mentioned. But n>-1.
Insuff.

S2: Insuff. could be n*p or -n*-p

1&2. Since n and p are i's. n>0.

So np>0 p is + or p>0

C
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09 Sep 2007, 22:00
St1:

St2:
n = +ve, p=+ve or n = -ve and p = -ve. Insufficient.

St1 and St2:
n > -1. Since n*p must be greater than 0, neither n nor p can be 0. So n must be positive and p must be positive. Sufficieint.

Ans C
09 Sep 2007, 22:00
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