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# If N and P denote the non-zero digits of a four-digit number

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If N and P denote the non-zero digits of a four-digit number [#permalink]  11 Jan 2009, 18:09
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If N and P denote the non-zero digits of a four-digit number NNPP, is NNPP divisible by 4?

(1) NPP is divisible by 8
(2) NPP is divisible by 4
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Re: DS-4 digit number [#permalink]  11 Jan 2009, 18:29
vscid wrote:
If N and P denote the non-zero digits of a four-digit number NNPP, is NNPP divisible by 4?

(1) NPP is divisible by 8
(2) NPP is divisible by 4

both are individually enough.
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tusharvk

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Re: DS-4 digit number [#permalink]  16 Jan 2009, 09:24
tusharvk wrote:
vscid wrote:
If N and P denote the non-zero digits of a four-digit number NNPP, is NNPP divisible by 4?

(1) NPP is divisible by 8
(2) NPP is divisible by 4

both are individually enough.

Can you please explain why if NPP is divisible by 8, so NNPP is too?

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Re: DS-4 digit number [#permalink]  16 Jan 2009, 12:43
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If N and P denote the non-zero digits of a four-digit number NNPP, is NNPP divisible by 4?

(1) NPP is divisible by 8
(2) NPP is divisible by 4

this is a Yes/ No question
a four digit number NNPP is divisible by 4 if pp is divisible by 4.
if pp is divisible by 4 the answer is yes
if pp is not divisible by 4 the answer is no

1. NPP is divisible by 8 ......( rule for divisibility by 8 says if the last three digits are divisible by 8 then the number is divisible by 8 .....and a number which is divisible by 8 is always divisible by 4 as 4 is a factor of 8) so statement 1 is sufficient.

2. NPP is divisible by 4 implies PP is divisible by 4
statement 2 is sufficient .

Re: DS-4 digit number   [#permalink] 16 Jan 2009, 12:43
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