Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If n and r are positive integers and r is the remainder when [#permalink]
30 Aug 2006, 10:08

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

If n and r are positive integers and r is the remainder when 27 is divided by n, r=?
1). When 20 is divided by n, remainder is 7.
2). When 27 is divided by n, quotient is 2, remainder is r.

Re: tough remainder DS [#permalink]
30 Aug 2006, 10:30

apollo168 wrote:

If n and r are positive integers and r is the remainder when 27 is divided by n, r=? 1). When 20 is divided by n, remainder is 7. 2). When 27 is divided by n, quotient is 2, remainder is r.

St1:
20 = nx + 7
i.e nx must be 13. So either n = 1 or n = 13. But n must be greater than 7 to get a remainder of 7. So n = 13.
Reaminder of 27/13 = 1: SUFF

St2:
27 = 2n + r
So r must be an odd integer. So
r =1 for n = 13
r = 3 for n = 12
r = 5 for n = 11
r = 7 for n = 10
: INSUFF _________________

St1: 20 = nx + 7 i.e nx must be 13. So either n = 1 or n = 13. But n must be greater than 7 to get a remainder of 7. So n = 13. Reaminder of 27/13 = 1: SUFF

St2: 27 = 2n + r So r must be an odd integer. So r =1 for n = 13 r = 3 for n = 12 r = 5 for n = 11 r = 7 for n = 10 : INSUFF

Statement 1 is sufficient as Dahiya has pointed out.

Statement 2, upon closer inspection, is just restating the question. No new information can be attained. What necromonger referred to as "twin trouble." Insuff.

I arrived upon A as well but without much of the hassle or even putting in numbers Should've prolly double checked!!!

Acc to the problem statement we have to find r if 27 = nk + r.

Now the first statement gives you 20 = nk + 7, so by substituting nk = 13 in the first statement we can solve for r. (since both should be true for all k). Therefore, SUFF.

In the second statement we get 27 = 2n + r, which is really a specific solution for the problem statement itself - like psdahiya says, no new information. INSUFF.

Hello everyone! Researching, networking, and understanding the “feel” for a school are all part of the essential journey to a top MBA. Wouldn’t it be great... ...

As part of our focus on MBA applications next week, which includes a live QA for readers on Thursday with admissions expert Chioma Isiadinso, we asked our bloggers to...

Booth allows you flexibility to communicate in whatever way you see fit. That means you can write yet another boring admissions essay or get creative and submit a poem...