prasannajeet wrote:

Hi Bunuel

Can it be right if go like the following way?

given (-n)^2<1/100

=>n^2<1/00

=>n<1/10

Now Q ask us to find reciprocal of n

So take the reciprocal on both side simply we get

1/n<10 Ans

No.

Given: n < 0

\(n^2 < (1/100)\)

Note that you will not use -n because n is negative. n already includes the negative sign.

When you take square root, you get |n| < 1/10 (and not n < 1/10). This means -1/10 < n < 1/10. But since n < 0, -1/10 < n < 0.

We need to find the value of reciprocal i.e. 1/n.

n > -1/10

1/n < -10 Note that in an inequality, if both sides of the inequality have the same sign (positive or negative), the sign of inequality (<, >) flips when you take the reciprocal. Here both sides are negative so sign flips.

(Or do what Bunuel did: multiply by -10/n.)

So reciprocal is less than -10.

Instead, I would do this question by thinking of some numbers and figuring out the logic - discussed here:

if-n-denotes-a-number-to-the-left-of-0-on-the-number-line-91659.html#p811517 _________________

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