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If n is a positive integer and 10^n is a factor of m, what

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If n is a positive integer and 10^n is a factor of m, what [#permalink] New post 26 May 2013, 07:56
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If n is a positive integer and 10^n is a factor of m, what is the value of n?

(1) m is the product of the first positive 40 numbers .
(2) n > 8*m/40!
[Reveal] Spoiler: OA

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Last edited by Bunuel on 26 May 2013, 08:16, edited 1 time in total.
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Re: If n is a positive integer and 10n is a factor of m, what is [#permalink] New post 26 May 2013, 08:18
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If n is a positive integer and 10^n is a factor of m, what is the value of n?

Given that m=10^n*k for some positive integer k.

(1) m is the product of the first positive 40 numbers --> m=40! --> 40!=10^n*k. The number of trailing zeros of 40! is 40/5+40/25=8+1=9 (check here: everything-about-factorials-on-the-gmat-85592.html). So, 40! ends with 9 zeros, which means that n could be from 1 to 9, inclusive. Not sufficient.

(2) n > 8*m/40!. Clearly not sufficient.

(1)+(2) From (1) m=40!, thus from (2) n>\frac{8*40!}{40!}=8. Since from (1) we also have that 1\leq{n}\leq{9}, then n=9. Sufficient.

Answer: C.

Similar question to practice: if-d-is-a-positive-integer-and-f-is-the-product-of-the-first-126692.html

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Re: If n is a positive integer and 10n is a factor of m, what is   [#permalink] 26 May 2013, 08:18
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If n is a positive integer and 10^n is a factor of m, what

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