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if n is a positive integer and k=5.1*10^n, what is the value

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Manager
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if n is a positive integer and k=5.1*10^n, what is the value [#permalink] New post 17 Feb 2008, 17:41
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A
B
C
D
E

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if n is a positive integer and k=5.1*10^n, what is the value of k?
1. 6000<k<500000
2.k^2=2,.601*10^9
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Re: DS:n [#permalink] New post 17 Feb 2008, 18:54
In order to solve this: we needed to know “n”.

1. 6000 < k < 500000

K can have 51000 and 510000, but 510000 is out of range.
51000 = 5.1 * 10 ^ n Therefore n = 4 (Sufficient)

2. k^2=2, .601*10^9
K ^2 = 25 * 10 ^8 (approximate)
K = +/- 5 * 10 ^ 4
Since n is positive, but we have tow possibilities of k – not sufficient

Answer: A
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Re: DS:n [#permalink] New post 18 Feb 2008, 14:00
hanumayamma wrote:
In order to solve this: we needed to know “n”.

1. 6000 < k < 500000

K can have 51000 and 510000, but 510000 is out of range.
51000 = 5.1 * 10 ^ n Therefore n = 4 (Sufficient)

2. k^2=2, .601*10^9
K ^2 = 25 * 10 ^8 (approximate)
K = +/- 5 * 10 ^ 4
Since n is positive, but we have tow possibilities of k – not sufficient

Answer: A


answer is D. It means that data2 should be sufficient. Can anyone explain how is it possible?
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Re: DS:n [#permalink] New post 18 Feb 2008, 15:06
D

For #2, k value has to be +ve because for a +ve value of n, k can not be -ve.
Re: DS:n   [#permalink] 18 Feb 2008, 15:06
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if n is a positive integer and k=5.1*10^n, what is the value

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