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# If n is a positive integer and n^2 is divisible by 72, then

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Intern
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If n is a positive integer and n^2 is divisible by 72, then [#permalink]

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07 Oct 2005, 02:51
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is

a) 6
b) 12
c) 24
d) 36
e) 48
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07 Oct 2005, 03:10
hi, your question is unclear , could you please re-post it?!!
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07 Oct 2005, 04:37
I pick b.

72=3^2*2^3

n is at least 3*2^2
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07 Oct 2005, 14:33
n^2 is divisible by 72:
So,
n^2 = 72, n is not an integer
n^2 = 144, n = 12
...
n^2 = 576, n = 24
...
n^2 = (72)(72), n = 72

This implies that all perfect squares of n are multiples of 12. So 12 it is.
07 Oct 2005, 14:33
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# If n is a positive integer and n^2 is divisible by 72, then

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