If n is a positive integer and n^2 is divisible by 72, then the largest possible positive integer that must divide n is
I am confused what is being asked here.
Please explain your answers
Folks, let me give a generalised answers to questions like these. Once we know the basic way to answer questions like these as yezz
said we can get that 700+
Concentrate for the next 5 minutes pleaseeeeeeee
given that n^2 is divisible by 72
So n^2 = 72xk (which means 72xk must be perfect squares)
n^2 = 9x4x2xk
Clearly 9 and 4 are perfect squares. So k must be minimum 2 to make the entire number a perfect square.
SO the general form of the k will be 2 x any perfect square.
ie k = 2x p^2
So n^2 = 9x4x2x2xp^2
hence n = 3x2x2xp
So the general value of n will 12xp, which must be divisible by12
I think i am lucid,
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