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# If n is a positive integer and n2 is divisible by 72, then

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Manager
Joined: 03 Jul 2007
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If n is a positive integer and n2 is divisible by 72, then [#permalink]

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16 Dec 2007, 09:47
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If n is a positive integer and n2 is divisible by 72, then the largest positive integer that must divide n is

a, 6
b, 12
c, 24
d, 36
e, 48

Thanks
SVP
Joined: 29 Aug 2007
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Re: OG #169 [#permalink]

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16 Dec 2007, 10:01
pinal2 wrote:
If n is a positive integer and n2 is divisible by 72, then the largest positive integer that must divide n is

a, 6
b, 12
c, 24
d, 36
e, 48

Thanks

not sure whether the question is properly worded:

n^2 = 72k
n^2 = 2 x 2 x 2 x 3 x 3 x k
n = 2x3 sqrt(2k)
has to be a minimum of 2 to be n an integer
so n = 2x3x2 = 12
Manager
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16 Dec 2007, 14:46
You are correct. I apologize. the n2 should be n^2.

Thanks for your explanation.
16 Dec 2007, 14:46
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# If n is a positive integer and n2 is divisible by 72, then

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