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Re: If n is a positive integer, is n^3 n divisible by 4 ? (1) n [#permalink]
18 Apr 2012, 03:11

In the statement one when we express n=2k+1, why cant we take k=0, in that case n=1 and the product will be zero...Can we say then zero is divisible by 4?

Re: If n is a positive integer, is n^3 n divisible by 4 ? (1) n [#permalink]
18 Apr 2012, 03:14

Expert's post

pavanpuneet wrote:

In the statement one when we express n=2k+1, why cant we take k=0, in that case n=1 and the product will be zero...Can we say then zero is divisible by 4?

Zero is a divisible by every integer, except zero itself. Or which is the same: zero is a multiple of every integer, except zero itself. Integer a is a multiple of integer b means that a is "evenly divisible" by b, i.e., divisible by b without a remainder. Now, since zero/integer=integer then zero is a multiple of every integer (except zero itself).

Re: If n is a positive integer, is n^3 n divisible by 4 ? (1) n [#permalink]
15 Jun 2012, 14:37

Bunuel wrote:

pavanpuneet wrote:

In the statement one when we express n=2k+1, why cant we take k=0, in that case n=1 and the product will be zero...Can we say then zero is divisible by 4?

Zero is a divisible by every integer, except zero itself. Or which is the same: zero is a multiple of every integer, except zero itself. Integer a is a multiple of integer b means that a is "evenly divisible" by b, i.e., divisible by b without a remainder. Now, since zero/integer=integer then zero is a multiple of every integer (except zero itself).

Re: If n is a positive integer, is n^3 n divisible by 4 ? (1) n [#permalink]
15 Jun 2012, 18:02

1

This post received KUDOS

Expert's post

solarzj wrote:

Bunuel wrote:

pavanpuneet wrote:

In the statement one when we express n=2k+1, why cant we take k=0, in that case n=1 and the product will be zero...Can we say then zero is divisible by 4?

Zero is a divisible by every integer, except zero itself. Or which is the same: zero is a multiple of every integer, except zero itself. Integer a is a multiple of integer b means that a is "evenly divisible" by b, i.e., divisible by b without a remainder. Now, since zero/integer=integer then zero is a multiple of every integer (except zero itself).