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Sorry, i cannot seem to get the concept behind solving this and trying to break it down. Hope you can be patient enough to explain...

vipin7um, why is the simplified question stem [n(n+1)(n-1) all over 4] only divisible if n is odd? whether n is odd or even, the numerator will always give an even number. then i only need to determine from the statements whether that number is divisible by 4 right?

Sorry, i cannot seem to get the concept behind solving this and trying to break it down. Hope you can be patient enough to explain...

vipin7um, why is the simplified question stem [n(n+1)(n-1) all over 4] only divisible if n is odd? whether n is odd or even, the numerator will always give an even number. then i only need to determine from the statements whether that number is divisible by 4 right?

Actually, let me correct myself. n(n+1)(n-1) would be definitely divisible by 4 if n is odd. It will be divisible by 4, if n is multiple of 4 as well.

This is so because the above expression is nothing but product of three consecutive numbers, n being the middle number. So if n is odd, then the number that precedes it, and the number that follows it will be even. Which means the product will have at least two even numbers and hence it will be divisible by four.

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I started running back in 2005. I finally conquered what seemed impossible. Not sure when I would be able to do full marathon, but this will do for now...