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Sorry, i cannot seem to get the concept behind solving this and trying to break it down. Hope you can be patient enough to explain...

vipin7um, why is the simplified question stem [n(n+1)(n-1) all over 4] only divisible if n is odd? whether n is odd or even, the numerator will always give an even number. then i only need to determine from the statements whether that number is divisible by 4 right?

Sorry, i cannot seem to get the concept behind solving this and trying to break it down. Hope you can be patient enough to explain...

vipin7um, why is the simplified question stem [n(n+1)(n-1) all over 4] only divisible if n is odd? whether n is odd or even, the numerator will always give an even number. then i only need to determine from the statements whether that number is divisible by 4 right?

Actually, let me correct myself. n(n+1)(n-1) would be definitely divisible by 4 if n is odd. It will be divisible by 4, if n is multiple of 4 as well.

This is so because the above expression is nothing but product of three consecutive numbers, n being the middle number. So if n is odd, then the number that precedes it, and the number that follows it will be even. Which means the product will have at least two even numbers and hence it will be divisible by four.

It’s been a long time, since I posted. A busy schedule at office and the GMAT preparation, fully tied up with all my free hours. Anyways, now I’m back...

Ah yes. Funemployment. The time between when you quit your job and when you start your MBA. The promised land that many MBA applicants seek. The break that every...

It is that time of year again – time for Clear Admit’s annual Best of Blogging voting. Dating way back to the 2004-2005 application season, the Best of Blogging...