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If n is a positive integer, then n(n+1)(n+2) is

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Re: n is a positive integer [#permalink] New post 01 Sep 2011, 18:53
The product of two even integer is always divisible by 4. So, the definite answer is E.
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Re: If n is positive integer, then n(n+)(n+2) is [#permalink] New post 27 Aug 2013, 01:56
I am assuming the expression is n(n+1)(n+2)

a) This not true. If n is even, (n+1) will be odd and if n is odd (n+1) will be even. It is sufficient for any one of the terms to be even to make the entire expression even.

b) For the same reasons as "a" this is alos not true.

c) This is also not true. It is sufficient for (n+1) alone to be a multiple of 3 for the entire expression to be divisible by 3. eg : n=2

e) Whenever n is even, (n+2) will also be even. Hence the expression will have two even integers and hence is always divisible by 4.
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Re: PS: Odd/Even and Divisibility [#permalink] New post 30 Oct 2013, 12:08
avdxz wrote:
If n is a positive integer, then n(n+1)(n+2) is

(A) even only when n is even
(B) even only when n is odd
(C) odd whenever n is odd
(D) divisible by 3 only when n is odd
(E) divisible by 4 whenever n is even


E..whenever ..the equation is a product of three consecutive numbers and when the first is even the last will also be an even nmber...thus we will have two two's in the final product and thus the number will be divisible by four...
Re: PS: Odd/Even and Divisibility   [#permalink] 30 Oct 2013, 12:08
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