Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

For me, the fastest way to get to the answer is by first reducing the fraction by dividing Num and Den by 7*11=77 and then simply start multiplying remaining numbers in the Numerator until I get one given in the answer choices (which would be 26=2*13)

The main stem reduces to 2*3*5*7*11*13/7*11*k i.e
2*3*5*13/k

So k must be product of any combination of product of these numbers. Now look at the answers and you will see that only 26 (2*13) fits. _________________

Re: Fastest way to solve [#permalink]
27 Jun 2006, 20:14

B

If N is an integer, k has to be a factor of N where N = (2x3x5x13)/k, since 77 is a factor of 7x11. So any product of the 4 numbers (2,3,5,13) besides the number themselves is considered a factor of (2x3x5x13) if N is an integer....6, 10, 26, 15, 39, 65, 30, 78, 195.

Originally posted on MIT Sloan School of Management : We are busy putting the final touches on our application. We plan to have it go live by July 15...