you guys make this look soo eazy...how many of you did this in under 2 mins? I must say you guys are great...I think if you can do this in under 1 min...you are math is definetly solid...

OA is 4...

it took me 4 mins...to figure this out...

n^4=32*m where m is an integer...

so we can break 32 down to its prime factors...2^5....

n^4=2^5 * m...so we know that n is at the least has 2^2 as its prime factor...

think of it like, if n^4 was equal to 2^4 then we know that n=2m....right!

anyway back to the problem

so n at a minimum is 4...

so we now get

4x=32m+c (where m is an integer, c is an integer and is meant to be a reminader)

so in order for x to be an integer...

x=8m+c/4 (c has to be 4 or a multiple of it!)

4 it is...

not sure..if what i did makes sense but I get the same ans as you...which so happens to be the OA...will post OE as soon as I get it...

so lets do 4/32 what is the remainder