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1) n^2-1 is an odd integer 2) 3n+4 is an even integer

According to GMAT answer it is D but I disagree and have to say it is E because n can be 0 which is not an even number while satisfying both requirement.

Any thoughts?

Hello Ekin, welcome to the Gmat Club.

First of all I must say that zero IS an even integer, though it's neither positive nor negative.

Even number (even integer) \(n\) is of the form \(n=2k\), where \(k\) is an integer, so for \(k=0\), \(n=2*0=0\).

As for the question:

(1) \(n^2-1=(n-1)(n+1)=odd\) --> both \(n-1\) and \(n+1\) must be odd to produce an odd integer when multiplied, hence \(n\) is be even. Sufficient.

(2) \(3n+4=even\) --> \(3n\) must be even --> \(n\) must even. Sufficient.

1) n^2-1 is an odd integer 2) 3n+4 is an even integer

According to GMAT answer it is D but I disagree and have to say it is E because n can be 0 which is not an even number while satisfying both requirement.

If n is an integer, is n even? (1) (n^2) - 1 is an odd integer. (2) 3n + 4 is an even integer.

I personally think it is E, because putting n as 0, both the condition are insufficient. But the OA does not include 0 as one of the conditions to check.

Please explain or am I missing something here?

Thanks, Sandeep Nerli (Taking GMAT on 30th of June, 2010)

Re: OFFICIAL GUIDE 12th Edition DS Q24 [#permalink]

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11 Jun 2010, 01:30

IMO A.

Why n=0 is not a valid condition?

sandeepnerli wrote:

If n is an integer, is n even? (1) (n^2) - 1 is an odd integer. (2) 3n + 4 is an even integer.

I personally think it is E, because putting n as 0, both the condition are insufficient. But the OA does not include 0 as one of the conditions to check.

Please explain or am I missing something here?

Thanks, Sandeep Nerli (Taking GMAT on 30th of June, 2010)

Re: OFFICIAL GUIDE 12th Edition DS Q24 [#permalink]

Show Tags

11 Jun 2010, 02:29

Hi,

The question clearly states that n is an integer, so n can be 0 and I agree that for n= 0 both the statements hold true, but since 0 is neither negative nor positive, I think the answer should be E, not D

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