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Re: Question need help [#permalink]
10 Feb 2010, 12:42
Expert's post
Ekin4112 wrote:
If n is an integer is n even?
1) n^2-1 is an odd integer 2) 3n+4 is an even integer
According to GMAT answer it is D but I disagree and have to say it is E because n can be 0 which is not an even number while satisfying both requirement.
Any thoughts?
Hello Ekin, welcome to the Gmat Club.
First of all I must say that zero IS an even integer, though it's neither positive nor negative.
Even number (even integer) \(n\) is of the form \(n=2k\), where \(k\) is an integer, so for \(k=0\), \(n=2*0=0\).
As for the question:
(1) \(n^2-1=(n-1)(n+1)=odd\) --> both \(n-1\) and \(n+1\) must be odd to produce an odd integer when multiplied, hence \(n\) is be even. Sufficient.
(2) \(3n+4=even\) --> \(3n\) must be even --> \(n\) must even. Sufficient.
Re: Question need help [#permalink]
14 Mar 2010, 02:12
Ekin4112 wrote:
If n is an integer is n even?
1) n^2-1 is an odd integer 2) 3n+4 is an even integer
According to GMAT answer it is D but I disagree and have to say it is E because n can be 0 which is not an even number while satisfying both requirement.
OFFICIAL GUIDE 12th Edition DS Q24 [#permalink]
10 Jun 2010, 23:27
If n is an integer, is n even? (1) (n^2) - 1 is an odd integer. (2) 3n + 4 is an even integer.
I personally think it is E, because putting n as 0, both the condition are insufficient. But the OA does not include 0 as one of the conditions to check.
Please explain or am I missing something here?
Thanks, Sandeep Nerli (Taking GMAT on 30th of June, 2010)
Re: OFFICIAL GUIDE 12th Edition DS Q24 [#permalink]
11 Jun 2010, 00:30
IMO A.
Why n=0 is not a valid condition?
sandeepnerli wrote:
If n is an integer, is n even? (1) (n^2) - 1 is an odd integer. (2) 3n + 4 is an even integer.
I personally think it is E, because putting n as 0, both the condition are insufficient. But the OA does not include 0 as one of the conditions to check.
Please explain or am I missing something here?
Thanks, Sandeep Nerli (Taking GMAT on 30th of June, 2010)
Re: OFFICIAL GUIDE 12th Edition DS Q24 [#permalink]
11 Jun 2010, 01:29
Hi,
The question clearly states that n is an integer, so n can be 0 and I agree that for n= 0 both the statements hold true, but since 0 is neither negative nor positive, I think the answer should be E, not D
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