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# If n is an odd integer greater than 1, is n prime? (1) n is

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If n is an odd integer greater than 1, is n prime? (1) n is [#permalink]  29 Nov 2007, 11:43
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If n is an odd integer greater than 1, is n prime?

(1) n is a factor of 56
(2) 14 is a factor of 2n.
VP
Joined: 09 Jul 2007
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Re: DS factors [#permalink]  29 Nov 2007, 11:50
young_gun wrote:
If n is an odd integer greater than 1, is n prime?

(1) n is a factor of 56
(2) 14 is a factor of 2n.

1. not suff. as n=1, 2, 3, 4...

2. not suff. as n=7, 14,...

1 and 2

n=7, 14, 28...

E.
CEO
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Re: DS factors [#permalink]  29 Nov 2007, 12:13
Ravshonbek wrote:
young_gun wrote:
If n is an odd integer greater than 1, is n prime?

(1) n is a factor of 56
(2) 14 is a factor of 2n.

1. not suff. as n=1, 2, 3, 4...

2. not suff. as n=7, 14,...

1 and 2

n=7, 14, 28...

E.

I disagree

1) 56 --> 7 * 8 --> 7 *2*2*2 n is an odd integer GREATER THAN 1.

So N can only be 7. If u try and multpily 7 by any of the other factors, it becomes even and thus cannot be N.

Suff.

2) 2n/14 --> 2*n/2*7 --> n/7 N could be 7, 21, 35 etc...

So could be prime or not

A
VP
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Re: DS factors [#permalink]  29 Nov 2007, 12:36
Ravshonbek wrote:
young_gun wrote:
If n is an odd integer greater than 1, is n prime?

(1) n is a factor of 56
(2) 14 is a factor of 2n.

1. not suff. as n=1, 2, 3, 4...

2. not suff. as n=7, 14,...

1 and 2

n=7, 14, 28...

E.

thanks i missed that "ODD" integer point in the stem. thus put all factor integers in 1.
Manager
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good pick up Gmatblackbelt, i missed that too.
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yep, got A.

From statement 1, prime factorization of 56 gives 2,2,2,7. Only 7 fits the bill as being odd and greater than 1. Sufficient

From statement 2, we just know that n can be any multiple of 7, and those odd values, i.e. 7, 21, could be prime or not. So not sufficient.
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