C for me
If n = p + r, where n, p, and r are positive integers and n is odd, does p equal 2?
(1) p and r are prime numbers. -> n is odd thus of P,R one has to be even n the other odd
now we don't know which is even,which odd thus insuff.
(2) r ≠ 2 = does not provide information -> insuff
comb 1& 2 p&r are prime and one has to be even and the other odd, using stmt-2 r is not 2 thus p=2 thus C