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If p and n are positive integers and p > n, what is the rema

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If p and n are positive integers and p > n, what is the rema [#permalink] New post 10 May 2010, 09:34
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If p and n are positive integers and p > n, what is the remainder when p^2 - n^2 is divided by 15?

(1) The remainder when p + n is divided by 5 is 1.
(2) The remainder when p - n is divided by 3 is 1.
[Reveal] Spoiler: OA

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Re: DS8 [#permalink] New post 10 May 2010, 15:36
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If p and n are positive integers and p>n, what is the remainder when p^2 - n^2 is divided by 15?

First of all p^2 - n^2=(p+n)(p-n).

(1) The remainder when p + n is divided by 5 is 1. No info about p-n. Not sufficient.

(2) The remainder when p - n is divided by 3 is 1. No info about p+n. Not sufficient.

(1)+(2) "The remainder when p + n is divided by 5 is 1" can be expressed as p+n=5t+1 and "The remainder when p - n is divided by 3 is 1" can be expressed as p-n=3k+1.

Multiply these two --> (p+n)(p-n)=(5t+1)(3k+1)=15kt+5t+3k+1, now first term (15kt) is clearly divisible by 15 (r=0), but we don't know about 5t+3k+1. For example t=1 and k=1, answer r=9 BUT t=7 and k=3, answer r=0. Not sufficient.

OR by number plugging: if p+n=11 (11 divided by 5 yields remainder of 1) and p-n=1 (1 divided by 3 yields remainder of 1) then (p+n)(p-n)=11 and remainder upon division 11 by 15 is 11 BUT if p+n=21 (21 divided by 5 yields remainder of 1) and p-n=1 (1 divided by 3 yields remainder of 1) then (p+n)(p-n)=21 and remainder upon division 21 by 15 is 6. Not sufficient.

Answer: E.
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Re: DS8 [#permalink] New post 04 Oct 2010, 13:55
Hi Bunuel,
According to my understanding ans should be c..
given (p+n)/5 = rem(1)
(p-n)/3= rem(1)
so (p^2 - n^2)/15 = (p+n)/5 * (p-n)/3...
so remainder will be equal to 1*1 = 1

please correct me where I am wrong.
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Re: DS8 [#permalink] New post 04 Oct 2010, 14:05
sudhanshushankerjha wrote:
Hi Bunuel,
According to my understanding ans should be c..
given (p+n)/5 = rem(1)
(p-n)/3= rem(1)
so (p^2 - n^2)/15 = (p+n)/5 * (p-n)/3...
so remainder will be equal to 1*1 = 1

please correct me where I am wrong.


Red part is not correct.

There are both algebraic and number plugging approaches in my previous post showing that answer is E. Yuo can check it yourself:

If p=6 and n=5 then p+n=11 (11 divided by 5 yields remainder of 1) and p-n=1 (1 divided by 3 yields remainder of 1) then (p+n)(p-n)=11 and remainder upon division 11 by 15 is 11

If p=11 and n=10 then p+n=21 (21 divided by 5 yields remainder of 1) and p-n=1 (1 divided by 3 yields remainder of 1) then (p+n)(p-n)=21 and remainder upon division 21 by 15 is 6.

Two different answers. Not sufficient.
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RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!! ,11 Mixed Questions NEW!!!, 12 Fresh Meat NEW!!!

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!, 11 New DS set. NEW!!!


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Re: DS8   [#permalink] 04 Oct 2010, 14:05
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