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Re: DS - consecutive even [#permalink]
06 Jun 2007, 14:22
Caas wrote:
If p and q are consecutive even integers, is p>q?
1) p-2 and q+2 are consecutive even integers 2) p is prime
(1) if p-2 and q+2 are consecutive also, then it MUST be the case that p>q. Suff.
(2) p is prime, then it´s =2. If p and q are consecutive even integers, then q = 0 or 4 (even integer can be +ve, -ve, or 0), then we cannot know for sure whether p<>q. Insuff.
Re: DS - consecutive even [#permalink]
06 Jun 2007, 15:05
I'll go with A.
1) P-2 and q+2 are consecutive even integers.
take the sample numbers where both numbers are positive and both are negative. you will see that p>q is always true for p-2 and q +2 to be consecutive even integers. you can also test this eith {-2, 0} and {0, 2}. - sufficient
2) p is prime. q could be 0 or 4. for 0 p >q holds up but not for 4. - not sufficient
Hey guys,
when i first looked at it, it also thought it was A, but if yo uthink about it's not enough to just say that p IS greater the q. In this case q is greater than p. (from the second option, where p is prime) The question asks if p>q, in this case you could you with certainty that it is not, therefore D, wither statement is suffiecient. One proves that p>q, and the other that P<q. Who cares if it is or not, point is that you could say it with certinty, and this is what GMAT wants.
For this DS question, I will examine each statement alone.
What's asked: is p>q ?
What's given: p and q are consecutive even integers
What do we know?
either p = q+2 or p = q-2
1) p-2 and q+2 are consecutive even integers
-------------------------------------------------------
if p = q-2, then p-2 = q-4 which can never be a consecutive even integer after or before q+2
Thus, p = q+2 and hence p>q
Statement 1 is sufficient
2) p is prime
----------------
We know that p is even, and the only even prime integer is 2. Since q and p are consecutive even integers, q can be either 0 or 4.