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If p and q are integers and neither p nor q is equal to 0,

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If p and q are integers and neither p nor q is equal to 0, [#permalink]

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New post 20 Jul 2009, 07:54
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If p and q are integers and neither p nor q is equal to 0, is p/q > q/p?
1. p^2 > q^2
2.p^3 > q^3

Allright. Simplifying the main equation,
p/q > q/p
= p^2 > q^2.

Is'nt this what the first stmt. is clearly stating?So I answered A and clearly it is wrong.Shed some light guys!
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Re: p and q are integers [#permalink]

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New post 20 Jul 2009, 08:11
Hey,
by simplifying that way, you assumed that p and q are both POSITIVE integers... stimulus says "integers"

let me look closer to it....
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Re: p and q are integers [#permalink]

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New post 20 Jul 2009, 08:34
If p and q were positive, then your approach would have been correct. But if exactly one of them is negative, then it won't hold true. You cannot multiply either sides by pq then because inequality sign reverses upon multiplication with a negative quantity.

You can test this with random numbers
take p = -3, q = -2....... ans is yes
take p = -3, q = 2........ ans is no

you could make out why stmt 2 was insufficient so not discussing that.

Combining, you know that whatever the sign, p is always greater than q (from stmt 2)
Yet, q could be a negative intgr while p were a positive one. in that case p/q < q/p

so ans should be E
Re: p and q are integers   [#permalink] 20 Jul 2009, 08:34
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If p and q are integers and neither p nor q is equal to 0,

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