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If p and q are negative, is p/q > 1

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If p and q are negative, is p/q > 1 [#permalink] New post 07 Feb 2011, 06:08
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If p and q are negative, is p/q > 1

(1) The positive difference between p and q is 2.
(2) q - p < 1
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Re: Algebra DS [#permalink] New post 07 Feb 2011, 06:49
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rxs0005 wrote:
If p and q are negative, is p / q > 1


(1) The positive diff erence between p and q is 2.
(2) q - p < 1


If p and q are negative, is p / q > 1

Given: p<0 and q<0. Question: is \frac{p}{q}>1 --> multiply both sides by q and as it's negative flip the sign: is p<q? or is p-q<0?

(1) The positive diff erence between p and q is 2 --> |p-q|=2: either p-q>0 (answer NO) and p-q=2 or p-q<0 (answer YES) and p-q=-2. Not sufficient.

(2) q - p < 1 (p-q>-1) --> if q=-1 and p=-1 then the answer will be NO but if q=-1 and p=-1.5 then the answer will be YES. Not sufficient.

(1)+(2) As from (2) p-q>-1 then from (1) p-q=2 so p-q>0 and we have the answer NO. Sufficient.

Answer: C.
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Re: Algebra DS [#permalink] New post 07 Feb 2011, 07:00
Stmt 1: let p=-5, q=-3 Ans : YES, but as its given positive difference is 2 the values can be interchanged Ans : NO insuff

Stmt 2 : q - p < 1 --> q < 1 + p ,, p = -1, q=-2 Ans : NO. p = -3, q = -4, Ans : NO, insuff

Combining,, p = -2, q= -4, NO.. p=-1,q=-3 NO Suff..

very lengthy method.. can anyone pls post easier way to deal with this sort of probs
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Re: Algebra DS [#permalink] New post 03 Apr 2012, 19:43
Bunuel wrote:
rxs0005 wrote:
If p and q are negative, is p / q > 1


(1) The positive diff erence between p and q is 2.
(2) q - p < 1


If p and q are negative, is p / q > 1

Given: p<0 and q<0. Question: is \frac{p}{q}>1 --> multiply both sides by q and as it's negative flip the sign: is p<q? or is p-q<0?

(1) The positive diff erence between p and q is 2 --> |p-q|=2: either p-q>0 (answer NO) and p-q=2 or p-q<0 (answer YES) and p-q=-2. Not sufficient.


I'm very confused. First why do you have absolute value? How did you derive p-q>0? p-q<0? p-q=-2? Any way to demonstrate? or explain the concepts? Thank you very much.

rxs0005 wrote:
(2) q - p < 1 (p-q>-1) --> if q=-1 and p=-1 then the answer will be NO but if q=-1 and p=-1.5 then the answer will be YES. Not sufficient.


How can q and p both equal -1?

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Re: Algebra DS [#permalink] New post 04 Apr 2012, 00:35
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bohdan01 wrote:
Bunuel wrote:
rxs0005 wrote:
If p and q are negative, is p / q > 1


(1) The positive diff erence between p and q is 2.
(2) q - p < 1


If p and q are negative, is p / q > 1

Given: p<0 and q<0. Question: is \frac{p}{q}>1 --> multiply both sides by q and as it's negative flip the sign: is p<q? or is p-q<0?

(1) The positive diff erence between p and q is 2 --> |p-q|=2: either p-q>0 (answer NO) and p-q=2 or p-q<0 (answer YES) and p-q=-2. Not sufficient.


I'm very confused. First why do you have absolute value? How did you derive p-q>0? p-q<0? p-q=-2? Any way to demonstrate? or explain the concepts? Thank you very much.

rxs0005 wrote:
(2) q - p < 1 (p-q>-1) --> if q=-1 and p=-1 then the answer will be NO but if q=-1 and p=-1.5 then the answer will be YES. Not sufficient.


How can q and p both equal -1?



"The positive difference between p and q is 2" means that the distance between p and q is 2, which can be expressed as |p-q|=2. For example positive difference between -5 and -3 is 2: |-5-(-3)|=2.

Next:
Absolute value properties:
When x\leq{0} then |x|=-x, or more generally when some \ expression\leq{0} then |some \ expression|={-(some \ expression)}. For example: |-5|=5=-(-5);

When x\geq{0} then |x|=x, or more generally when some \ expression\geq{0} then |some \ expression|={some \ expression}. For example: |5|=5;

So, for |p-q|=2:
If p-q>0 then |p-q|=p-q=2 (example: p=-3 and q=-5);
If p-q<0 then |p-q|=-(p-q)=q-p=2 (example: p=-5 and q=-3);

Check Absolute Value chapter of Math Book for more: math-absolute-value-modulus-86462.html

As for p=q=-1: unless it is explicitly stated otherwise, different variables can represent the same number.

Hope it's clear.
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Re: If p and q are negative, is p / q > 1 (1) The positive [#permalink] New post 04 Apr 2012, 05:21
C

bookmarking

given p<0 & q<0

find
p/q>1 or p < q

(A) The positive diff erence between p and q is 2.

there |p-q| = 2
so we have

if (p-q) = 2 then p > q

(p-q) = -2 then q > p

datanot sufficient

(B) q - p < 1 or p-q > -1 (multiply both sides by -ve and flip the sign)

if(p>q)
p = -0.5
q = -1

then p-q > -1

if(p<q)
p = -1
q = -0.5

then p-q > -1

datanot sufficient

(C)

only possibility
if(p>q)
p = -0.5 / -3
q = -1 / -5
then p-q > -1
also if (p-q) = 2 then p > q


opposite not true
if(p<q)
p = -5
q = -3

(p-q) = -2 then q > p but p-q not > -1

then p-q > -1 [not possible]
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Re: If p and q are negative, is p / q > 1 (1) The positive [#permalink] New post 04 Apr 2012, 23:06
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rxs0005 wrote:
If p and q are negative, is p / q > 1


(1) The positive diff erence between p and q is 2.
(2) q - p < 1


It is a good question and you can solve it logically too.

Given p and q are negative so p/q must be positive (negative/negative). Whether p/q is greater than 1 depends on whether p < q. If p < q, then yes, p/q > 1 (if p is more negative, it has higher absolute value). Else p/q is not greater than 1.

So we have to find out whether p is less than q.

(1) The positive diff erence between p and q is 2.

This only tells us that the difference between them is 2. It doesn't tell us which one is greater so not sufficient.

(2) q - p < 1
This tells us that if q is greater than p, it is less than 1 greater than p. q can be equal to p or less than p but if it is greater than p, it is certainly less than 1 greater than p. This means (q = -1.2, p = -1.9), (q = -23, p = -23.4), (q = -3, p = -3), (q = -4, p = -2) are possible pairs (and many more). Again, we don't know whether p is greater or q so not sufficient.

Using both together, we know that the difference between p and q is 2 and if q is greater than p, it is less than 1 greater than p. Since the difference between them is 2, q cannot be greater than p so p must be greater than q. We can say that "No. p is not less than q."
Hence sufficient. Answer (C)
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Re: If p and q are negative, is p / q > 1 (1) The positive [#permalink] New post 06 Apr 2012, 22:26
rxs0005 wrote:
If p and q are negative, is p / q > 1

(1) The positive diff erence between p and q is 2.
(2) q - p < 1


st. (1) the +ve difference = |p-q| = 2
implies p-q > 0 or p-q < 0
if p-q > 0 then
p>q then p/q> 1

But if p-q < 0 then p<q or p/q cannot be greater than 1
anyway st. (1) gives two options which leads "insufficient"

st. (2) q-p<1 (this could be p-q < -1 which mean p-q> -1 )
implies q-p = 0 or q-p is -ve
if q-p=0then p/q > 1 is not possible

But if q-p is -ve then it gives different values of p and q which says both -
p/q>1 or p/q<1
however st.(2) insufficient

Combining together st. (1) and st. (2)
p-q > -1 and p-q =2 implies
p>q or we can say p/q>1
Sufficient

hope i got it correct frm bunnel and karishma
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Re: If p and q are negative, is p / q > 1 (1) The positive [#permalink] New post 07 Apr 2012, 03:36
Expert's post
rxs0005 wrote:
If p and q are negative, is p / q > 1

(1) The positive diff erence between p and q is 2.
(2) q - p < 1


st. (1) the +ve difference = |p-q| = 2
implies p-q > 0 or p-q < 0
if p-q > 0 then
p>q then p/q> 1

But if p-q < 0 then p<q or p/q cannot be greater than 1
anyway st. (1) gives two options which leads "insufficient"

|p-q| = 2 gives you two cases: Either p-q = 2 or q-p = 2
We do not know whether p is smaller than q.


st. (2) q-p<1 (this could be p-q < -1 which mean p-q> -1 )

q-p < 1 is the same as p-q > -1 (when you multiply both sides by -1)

implies q-p = 0 or q-p is -ve
if q-p=0then p/q > 1 is not possible

But if q-p is -ve then it gives different values of p and q which says both -
p/q>1 or p/q<1
however st.(2) insufficient

If q-p<1, q could be greater or p could be greater. So we again cannot figure whether p is smaller than q

Combining together st. (1) and st. (2)
p-q > -1 and p-q =2 implies
p>q or we can say p/q>1
Sufficient

Combining, stmnt 1 tells us that either p-q = 2 or q-p = 2. Stmnt 2 tells us that q-p<1. Hence q-p cannot be 2. Therefore, p-q must be 2. p must be greater than q. We know that p is greater so p/q is not greater than 1 (since p and q are both negative)
Answer (C).

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Re: If p and q are negative, is p / q > 1 (1) The positive [#permalink] New post 23 Apr 2012, 20:40
Guess this is a 700+ level problem.
Anyway, excellent explanation Karishma
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Re: If p and q are negative, is p / q > 1 (1) The positive [#permalink] New post 22 May 2012, 17:26
i was able to solve but within 3 minutes.... how to solve this question in less than 2 min.
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Re: If p and q are negative, is p / q > 1 (1) The positive [#permalink] New post 27 Nov 2012, 17:56
Luckily I went for the diagram and was able to do it in under 2 minutes.

Draw a line with 0 in the middle. p and q are both to the left of 0. We only know this much. We don't know their position with respect to 0, i. e we don't know whether q or p is closer to 0 or even whether p and q are the same number, both negative. Question asks whether p/q>1 meaning is p more negative than q? This suggests that the question is about the position of p and q with respect to each other and 0.

1. the positive difference between them is 2 suggests that the distance between p and q is 2 units. this only tells us the distance and not which one is more negative than the other. Not Sufficient.
2. q-p<1 suggests that the difference between the two is less than 1. but their degree of negativity is not clear. by itself, this statement points to the possibility that q and p may be the same number; -2-(-2)=0<1, or one of them could be slightly more negative and still have satisfy q-p<1. so Not Sufficient.

when you take 1 and 2 together, the possibility that the two are the same number is eliminated because 1 says that the two numbers are 2 units apart. so now, the number line will have p and q standing at 2 units apart and based on statement 2, q has to be more negative than p. Hence C.

vikram4689 wrote:
i was able to solve but within 3 minutes.... how to solve this question in less than 2 min.
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Re: Algebra DS [#permalink] New post 17 Feb 2014, 11:35
Bunuel wrote:
rxs0005 wrote:
If p and q are negative, is p / q > 1


(1) The positive diff erence between p and q is 2.
(2) q - p < 1


If p and q are negative, is p / q > 1

Given: p<0 and q<0. Question: is \frac{p}{q}>1 --> multiply both sides by q and as it's negative flip the sign: is p<q? or is p-q<0?

(1) The positive diff erence between p and q is 2 --> |p-q|=2: either p-q>0 (answer NO) and p-q=2 or p-q<0 (answer YES) and p-q=-2. Not sufficient.

(2) q - p < 1 (p-q>-1) --> if q=-1 and p=-1 then the answer will be NO but if q=-1 and p=-1.5 then the answer will be YES. Not sufficient.

(1)+(2) As from (2) p-q>-1 then from (1) p-q=2 so p-q>0 and we have the answer NO. Sufficient.

Hi Bunuel! Could you please explain to me, why you concluded from (1) + (2) that p-q>0? The question doesn't say that p and q are integers, so shouldn't the answer be E then? because p-q>-1 (from I) could mean that p-q<0 or p-q>0 ..

Answer: C.


Hi Bunuel! Could you please explain to me, why you concluded from (1) + (2) that p-q>0? The question doesn't say that p and q are integers, so shouldn't the answer be E then? because p-q>-1 (from I) could mean that p-q<0 or p-q>0 ..
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Re: Algebra DS [#permalink] New post 17 Feb 2014, 13:16
damamikus wrote:
Bunuel wrote:
rxs0005 wrote:
If p and q are negative, is p / q > 1


(1) The positive diff erence between p and q is 2.
(2) q - p < 1


If p and q are negative, is p / q > 1

Given: p<0 and q<0. Question: is \frac{p}{q}>1 --> multiply both sides by q and as it's negative flip the sign: is p<q? or is p-q<0?

(1) The positive diff erence between p and q is 2 --> |p-q|=2: either p-q>0 (answer NO) and p-q=2 or p-q<0 (answer YES) and p-q=-2. Not sufficient.

(2) q - p < 1 (p-q>-1) --> if q=-1 and p=-1 then the answer will be NO but if q=-1 and p=-1.5 then the answer will be YES. Not sufficient.

(1)+(2) As from (2) p-q>-1 then from (1) p-q=2 so p-q>0 and we have the answer NO. Sufficient.

Hi Bunuel! Could you please explain to me, why you concluded from (1) + (2) that p-q>0? The question doesn't say that p and q are integers, so shouldn't the answer be E then? because p-q>-1 (from I) could mean that p-q<0 or p-q>0 ..

Answer: C.


Hi Bunuel! Could you please explain to me, why you concluded from (1) + (2) that p-q>0? The question doesn't say that p and q are integers, so shouldn't the answer be E then? because p-q>-1 (from I) could mean that p-q<0 or p-q>0 ..


As @grumpytesttaker said the best way to solve such problems is to use the number line.

The question stem says that p and q are negative so we can have 2 scenarios (p to the left of q or p to the right of q)

Image

Now to definitively say whether p/q>1 we need to find if |p| > |q| as both are negative so there is no question of signs. Since both are negative nos |p| > |q| only if p is to the left of q on the Number Line. So we just need to find if p is to the left or right of q.

(1) |p - q| = 2, this means p and q have a separation of 2. But this is possible if p is to the left of q or p is to the right of q. So this statement doesn't help us. Not Sufficient.

Image

(2) q - p < 1, Since both nos are negative we can rewrite this statement as |p| - |q| < 1. Now if p is to the left of q (|p| > |q|) then the separation between p and q have to be less than 1.
But if p is to the right of q (|p| < |q|) then the separation can be anything. Since this statement doesn't say if p is to the left or right of q, it is Not Sufficient.

Image

(1) & (2) Now if we combine the 2 statements we can see that p cannot be to the left of q because (1) -- |p| - |q| = 2 and (2) -- |p| - |q| < 1 together is not possible.
So the only possibility is p is to the right of q, which answers the question, since |p| < |q| hence p/q < 1

Image

So (1) & (2) put together answers the question. Sufficient. Answer C
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Re: Algebra DS [#permalink] New post 18 Feb 2014, 00:28
Expert's post
damamikus wrote:
Bunuel wrote:
rxs0005 wrote:
If p and q are negative, is p / q > 1


(1) The positive diff erence between p and q is 2.
(2) q - p < 1


If p and q are negative, is p / q > 1

Given: p<0 and q<0. Question: is \frac{p}{q}>1 --> multiply both sides by q and as it's negative flip the sign: is p<q? or is p-q<0?

(1) The positive difference between p and q is 2 --> |p-q|=2: either p-q>0 (answer NO) and p-q=2 or p-q<0 (answer YES) and p-q=-2. Not sufficient.

(2) q - p < 1 (p-q>-1) --> if q=-1 and p=-1 then the answer will be NO but if q=-1 and p=-1.5 then the answer will be YES. Not sufficient.

(1)+(2) As from (2) p-q>-1 then from (1) p-q=2 so p-q>0 and we have the answer NO. Sufficient.

Hi Bunuel! Could you please explain to me, why you concluded from (1) + (2) that p-q>0? The question doesn't say that p and q are integers, so shouldn't the answer be E then? because p-q>-1 (from I) could mean that p-q<0 or p-q>0 ..

Answer: C.


Hi Bunuel! Could you please explain to me, why you concluded from (1) + (2) that p-q>0? The question doesn't say that p and q are integers, so shouldn't the answer be E then? because p-q>-1 (from I) could mean that p-q<0 or p-q>0 ..


Sure. From (1) we have two possible cases: p-q=2 or p-q=-2. Since from (1) we have that p-q>-1, then p-q\neq{-2}, thus p-q=2>0.

Does this make sense?
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Re: Algebra DS   [#permalink] 18 Feb 2014, 00:28
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If p and q are negative, is p/q > 1

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