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Re: DS from GMATPrep - good one [#permalink]
22 Sep 2008, 08:49

I find both statements independently as sufficient. A - 'coz when a number is divisible by 8,it's also divisible by 4.remainder 5 divided by 4 will always leave 1 as remainder. so from choice A ,1 will be remainder.

B- is sufficient 'coz any even number will be of the form 2x.so if p = sq(2a) + sq(2b)= 4[sq(a) + sq(b)].dividing such a number by 4 will always give remainder 0.

Re: DS from GMATPrep - good one [#permalink]
22 Sep 2008, 09:35

puneetpradhan wrote:

I find both statements independently as sufficient. A - 'coz when a number is divisible by 8,it's also divisible by 4.remainder 5 divided by 4 will always leave 1 as remainder. so from choice A ,1 will be remainder.

B- is sufficient 'coz any even number will be of the form 2x.so if p = sq(2a) + sq(2b)= 4[sq(a) + sq(b)].dividing such a number by 4 will always give remainder 0.

My answer is D.

How do you get even number? To me, stmt2 simply says that p = a^2 + b^2. For a=1 and b=2, p = 5 and remainder = 1 when divided by 4. For a=1 and b=3, p = 10 and remainder = 2 when divided by 4.