Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
It is "true" DS. We have not to solve the problem, we have to say that the problem can be solved.
1. There are total of 100 prime numbers between 1 and p+1 The condition unambiguously says that p is 100th prime number. So, we can write out all 100 consecutive primes numbers and find p. sufficient.
2. There are total of p prime numbers between 1 and 3912. the same logic as in the fist condition. sufficient.
I even dare to say that p=3911. Why? Because I did not remember any DS, in which 2 conditions will be sufficient separately and lead to different values. _________________
I even dare to say that p=3911. Why? Because I did not remember any DS, in which 2 conditions will be sufficient separately and lead to different values.
No. 3911 is a 541th prime number..... _________________
I even dare to say that p=3911. Why? Because I did not remember any DS, in which 2 conditions will be sufficient separately and lead to different values.
No. 3911 is a 541th prime number..... :?
Hey,
The color one is exactly what I want to learn from you, guys. I have the same logic approach as your. I think if it is a PS, maybe we must seat and list all the prime number from 2 to p+1. That is imppossible for me. That is why I need your hand! Thanks
No. 3911 is a 541th prime number. I think you do not need to seat a time to count each number. Right? _________________