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If P were negative even integer, -p will be positive and (-2)^P will be positive and the minimum value of m will be when p is -2, m = -(-2) + (-2)^-2, which = 1.75

If P were positive even integer, the minimum value of m will be when p is 2, m = -2 + (-2)^2, which is = 2

so m^3 > 1 always
Ok

2)p^3 <= -1
This means that p is a negative integer
For for p=-1, m =0.5, but p = -2, m= 2.25
so m^3 is not always >1
Nope

A)

Last edited by nocilis on 14 Jan 2005, 18:15, edited 1 time in total.

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