Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: MGMAT DS Statistics- Is Q + 5 an integer [#permalink]

Show Tags

03 Oct 2011, 10:15

maheshsrini wrote:

If P is divisible by 2, is Q + 5 an integer?

(1) The median of P and Q is not an integer.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

Date - P is even. The question is basically - Does Q is an integer?

So - Statement 1 - INSU. Lets say P=2,Q=3 ----> The answer is YES. P=2, Q=2.5 ----> The answer is NO.

statement 2 - SUFF. \((3p+q+q+10)/3 = Integer\)

3p/3 = p ----> Integer.

2Q+10/3 = Integer. we know that 10/3 is not an integer. therefore 2Q is not an integer as well. so 2q=not integer. Q = not integer/2 ----> Q is not an integer. _________________

Re: MGMAT DS Statistics- Is Q + 5 an integer [#permalink]

Show Tags

04 Oct 2011, 03:56

maheshsrini wrote:

If P is divisible by 2, is Q + 5 an integer?

(1) The median of P and Q is not an integer.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

2) (3P+Q+Q+10)/3=3P/3+2(Q+5)/3 3P/3=P(Even integer) 2(Q+5)/3=Even Integer {:Note: P=Even; Even+Even=Even} 2(Q+5)=3*Even integer Q+5=3*Even Integer/2=3*Integer{:Note: All Even integers contain at least ONE 2} "Q+5" must be an integer. {:Note: 3*Integer=Integer; Integer * Integer= Integer} Sufficient.

Re: MGMAT DS Statistics- Is Q + 5 an integer [#permalink]

Show Tags

26 Oct 2013, 12:30

144144 wrote:

maheshsrini wrote:

If P is divisible by 2, is Q + 5 an integer?

(1) The median of P and Q is not an integer.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

Date - P is even. The question is basically - Does Q is an integer?

So - Statement 1 - INSU. Lets say P=2,Q=3 ----> The answer is YES. P=2, Q=2.5 ----> The answer is NO.

statement 2 - SUFF. \((3p+q+q+10)/3 = Integer\)

3p/3 = p ----> Integer.

2Q+10/3 = Integer. we know that 10/3 is not an integer. therefore 2Q is not an integer as well. so 2q=not integer. Q = not integer/2 ----> Q is not an integer.

could there be more discussion on this one? I don't get how you go from knowing 10/3 is not an integer to knowing that 2Q is not an integer either...

Re: MGMAT DS Statistics- Is Q + 5 an integer [#permalink]

Show Tags

27 Oct 2013, 10:28

3

This post received KUDOS

Expert's post

AccipiterQ wrote:

144144 wrote:

maheshsrini wrote:

If P is divisible by 2, is Q + 5 an integer?

(1) The median of P and Q is not an integer.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

Date - P is even. The question is basically - Does Q is an integer?

So - Statement 1 - INSU. Lets say P=2,Q=3 ----> The answer is YES. P=2, Q=2.5 ----> The answer is NO.

statement 2 - SUFF. \((3p+q+q+10)/3 = Integer\)

3p/3 = p ----> Integer.

2Q+10/3 = Integer. we know that 10/3 is not an integer. therefore 2Q is not an integer as well. so 2q=not integer. Q = not integer/2 ----> Q is not an integer.

could there be more discussion on this one? I don't get how you go from knowing 10/3 is not an integer to knowing that 2Q is not an integer either...

If P is divisible by 2, is Q + 5 an integer?

P is divisible by 2 implies that P is an even integer --> P=2*integer, for some integer k.

(1) The median of P and Q is not an integer. The median of P and Q is \(\frac{P+Q}{2}=\frac{2*integer+Q}{2}=integer+\frac{Q}{2}\). So, we are given that \(integer+\frac{Q}{2}\) is not an integer. This means that Q/2 is not an integer, thus Q is not an even integer, which means that Q is either an odd integer or not an integer at all. Not sufficient.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer --> \(\frac{3P+Q+Q + 10}{3}=even\) --> \(3P+2Q+10=3*even=even\) --> \(2Q=even-3P-10=even-even-even=even\) --> \(2Q=even\) --> \(Q=\frac{even}{2}=integer\). Sufficient.

Re: If P is divisible by 2, is Q + 5 an integer? (1) The median [#permalink]

Show Tags

22 Nov 2014, 16:58

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

http://blog.ryandumlao.com/wp-content/uploads/2016/05/IMG_20130807_232118.jpg The GMAT is the biggest point of worry for most aspiring applicants, and with good reason. It’s another standardized test when most of us...

I recently returned from attending the London Business School Admits Weekend held last week. Let me just say upfront - for those who are planning to apply for the...