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Re: MGMAT DS Statistics- Is Q + 5 an integer [#permalink]

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03 Oct 2011, 10:15

maheshsrini wrote:

If P is divisible by 2, is Q + 5 an integer?

(1) The median of P and Q is not an integer.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

Date - P is even. The question is basically - Does Q is an integer?

So - Statement 1 - INSU. Lets say P=2,Q=3 ----> The answer is YES. P=2, Q=2.5 ----> The answer is NO.

statement 2 - SUFF. \((3p+q+q+10)/3 = Integer\)

3p/3 = p ----> Integer.

2Q+10/3 = Integer. we know that 10/3 is not an integer. therefore 2Q is not an integer as well. so 2q=not integer. Q = not integer/2 ----> Q is not an integer.
_________________

Re: MGMAT DS Statistics- Is Q + 5 an integer [#permalink]

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04 Oct 2011, 03:56

maheshsrini wrote:

If P is divisible by 2, is Q + 5 an integer?

(1) The median of P and Q is not an integer.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

2) (3P+Q+Q+10)/3=3P/3+2(Q+5)/3 3P/3=P(Even integer) 2(Q+5)/3=Even Integer {:Note: P=Even; Even+Even=Even} 2(Q+5)=3*Even integer Q+5=3*Even Integer/2=3*Integer{:Note: All Even integers contain at least ONE 2} "Q+5" must be an integer. {:Note: 3*Integer=Integer; Integer * Integer= Integer} Sufficient.

Re: MGMAT DS Statistics- Is Q + 5 an integer [#permalink]

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26 Oct 2013, 12:30

144144 wrote:

maheshsrini wrote:

If P is divisible by 2, is Q + 5 an integer?

(1) The median of P and Q is not an integer.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

Date - P is even. The question is basically - Does Q is an integer?

So - Statement 1 - INSU. Lets say P=2,Q=3 ----> The answer is YES. P=2, Q=2.5 ----> The answer is NO.

statement 2 - SUFF. \((3p+q+q+10)/3 = Integer\)

3p/3 = p ----> Integer.

2Q+10/3 = Integer. we know that 10/3 is not an integer. therefore 2Q is not an integer as well. so 2q=not integer. Q = not integer/2 ----> Q is not an integer.

could there be more discussion on this one? I don't get how you go from knowing 10/3 is not an integer to knowing that 2Q is not an integer either...

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer.

Date - P is even. The question is basically - Does Q is an integer?

So - Statement 1 - INSU. Lets say P=2,Q=3 ----> The answer is YES. P=2, Q=2.5 ----> The answer is NO.

statement 2 - SUFF. \((3p+q+q+10)/3 = Integer\)

3p/3 = p ----> Integer.

2Q+10/3 = Integer. we know that 10/3 is not an integer. therefore 2Q is not an integer as well. so 2q=not integer. Q = not integer/2 ----> Q is not an integer.

could there be more discussion on this one? I don't get how you go from knowing 10/3 is not an integer to knowing that 2Q is not an integer either...

If P is divisible by 2, is Q + 5 an integer?

P is divisible by 2 implies that P is an even integer --> P=2*integer, for some integer k.

(1) The median of P and Q is not an integer. The median of P and Q is \(\frac{P+Q}{2}=\frac{2*integer+Q}{2}=integer+\frac{Q}{2}\). So, we are given that \(integer+\frac{Q}{2}\) is not an integer. This means that Q/2 is not an integer, thus Q is not an even integer, which means that Q is either an odd integer or not an integer at all. Not sufficient.

(2) The average (arithmetic mean) of 3P, Q, and Q + 10 is an even integer --> \(\frac{3P+Q+Q + 10}{3}=even\) --> \(3P+2Q+10=3*even=even\) --> \(2Q=even-3P-10=even-even-even=even\) --> \(2Q=even\) --> \(Q=\frac{even}{2}=integer\). Sufficient.

Re: If P is divisible by 2, is Q + 5 an integer? (1) The median [#permalink]

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22 Nov 2014, 16:58

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