If p is the perimeter of rectangle Q, what is the value of p?
1) Each diagonal of rectangle Q has length 10.
2) The area of rectangle Q is 48
Just a question...if we know that it's a right triangle and the length of hypotenuse...can't we assume it's 6-8-10 right triangle right off the bat???
Hmmm, I think the definition of a rectangle states that "a four-sided figure with opposite sides of equal length and all its angles right angles". So a rectangle here could also mean a square. So we cannot assume its a 6-8-10 right triangle. The sides could be 10/sqrt2 as well.
So with that being said...(1) is insufficient.
(2) Let x and y be the sides of the rectangle. xy=48. Insufficient. As x and y could be sqrt 48.
(1) and (2) together, x^2 + y^2 = 10^2, and xy = 48
x and y are 6 or 8, since we are asked for 2(x+y), we could solve for the perimeter.
Answer is C.