Alex, on first look i was thinking: Ha ??!
But then i realized that i should be looking for a factorial,
which contains at least 6 multiples of 5.
The numer 30 (6*5) is the least number with this property.
30! contains 6 multiples of 5: 5,10,15,20,25,30
And more than 6 multiples of 2.
Therefore this number should end with 6 zeros.
( i hope this is the correct answer
, if it is.. good guess !)
Oh, no! Dookie, man, that was brilliant. I was lost on this at first, and I scrolled down, saw the first line of your response, and took off with it. You're totally right - it must have 6 fives and 6 twos.
BUT 25 had 2 5's! So 29 has it already! 30 takes it too far - with 30 you'll have 7 fives and all those two's - you're up by another factor of 10.
So the answer has to be A.
The confusing thing was that this problem insinuates that it's got exactly 7 digits, or at least, that's how I read it. But in fact, it's got plenty more than that...