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I think only R cannot be zero, otherwise both 1) and 2) do no make sense.

So this left either P or T can be zero, and let's look at each case:

T is zero:

T=0, R=-1, P=-4, P<R<T, and this matches 1) where P+R+T=5R. The average is -5/3 which is not equal to 5/2R. So 1) alone is sufficient to answer the question. We can eliminate B, C, & E.

P is zero:

P=0, R=1, T=3, P<R<T, and this matches 2) where P+T=3R. The average is 4/3 which is not equal to 5/2R. So 2) alone is good too. We can eliminate A and the answer is D.

I don't think we sud think that R can be zero as the question wud then be asking us if the avg of these three numbers is infinity (5/2R)...doesn't make sense to think R can be zero, atleast to me.

I have assumed that the question says 'is the average of them is equal to (5/2)* R? and not 5/(2*R). DLMD Is this correct?

(I have assumed so because if R were at the denominator, usually there is a statement stating that R<>0, and in this problem there was no such statement.)

Great to know you are joining Kellogg. A lot was being talked about your last minute interview on Pagalguy (all good though). It was kinda surprise that you got the...