Answer is A.
For any polygon, sum of interior angles = (n-2)*180.
A) (n-2)*180 is divisible by 16. Only one value of 'n' (n = 6) is possible.
B) (n-2)*180 is divisible by 15. 180 is divisible by 15. Therefore there are multiple possible values for 'n'.
Same strategy...only A is sufficient..since (n-2)*180 is always divisible by 15.
1. (N-2)*180/16 = (N-2)*45/4
SO (N-2) should be divisible by 4 and only when N= 6 its possible!!